Understanding the Effect of Perpendicular Components in Simple Harmonic Motion

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Homework Help Overview

The discussion revolves around understanding the effects of perpendicular components in the context of simple harmonic motion (SHM) and circular motion. The original poster questions the reasoning behind the assertion that a component of velocity, vsinθ, has no effect along a specified direction due to its perpendicularity to that direction.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to clarify why the perpendicular component vsinθ does not influence motion along the OY direction. Some participants suggest that this component does have an effect, indicating a potential misunderstanding of the relationship between the components and the motion involved.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the motion involved. Some guidance is offered regarding the representation of simple harmonic motion, but no consensus has been reached regarding the original poster's question.

Contextual Notes

There appears to be confusion regarding the notation used, specifically the reference to YOY' and its representation in the accompanying diagram, which some participants note is not visible.

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Homework Statement



Kindly go through the attachment.
(i) vcosθ in a direction parallel to OY.

(ii) vsinθ in the direction perpendicular to OY.

The component vsinθ has no effect along YOY' since it is perpendicular to OY
My doubt is "Why the perpendicularity of vsinθ to OY makes vsinθ to have no effect along YOY'?"

Homework Equations





The Attempt at a Solution


 

Attachments

  • velocity20of20simple20harmonic20motion_0.JPG
    velocity20of20simple20harmonic20motion_0.JPG
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id like to think this is circular motion and not simple harmonic motion.

"Why the perpendicularity of vsinθ to OY makes vsinθ to have no effect along YOY'?"

It does!
 
You can represent SHM with angular velocity. Anyway, i don't see Y' in your picture.
 
Sorry, it is YO
 

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