Velocity always aimed at rectilinearly moving particle

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SUMMARY

The discussion focuses on a physics problem involving two points, A and B, where point B moves rectilinearly with a uniform velocity \( u \) and point A always aims at B with a constant speed \( v \). The initial separation between A and B is \( L \), and the problem requires determining the time taken for them to collide and the equations of motion for A in terms of coordinates \( x \) and \( y \). The equations of motion are derived using relative motion principles and involve the relationships \( \frac{dx}{dt} = -v \cos \theta + u \) and \( \frac{dy}{dt} = -v \sin \theta \).

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Homework Statement


2 points A and B, B moves rectilinear with uniform velocity u and velocity of A is always aimed at B with magnitude being constant=v, initially, v is perpendicular to u and separation was L, time taken for them to collide? and equation of motion of A? (in terms of x and y with origin at initial position of A would be good, y along initial AB and X perpendicular to it and +ve x in direction of u...would be better but, at this point anything would be good) ?

Homework Equations


ds/dt=v

The Attempt at a Solution


for collision, we can take relative motion by fixing a coordinate plane at A and coordinates of B=(x,y) and dx/dt=-vcosθ+u and dy/dt=-vsinθ (couldnt really do anything with dr/dt=-v+ucosθ) dividing, dy/dx=vy/(vx-u(x2+y2)1/2) ⇒vx.dy-u(x2+y2)1/2).dy=vy.dx
doesnt form d(y/x)
at t=0, x=0,y=L at t=T,x=0,y=0
tried same thing with origin at initial A with tanθ=L-y/ut-x and dx/dt=vcosθ and dy/dt=vsinθ and put value of θ at t=0, x=0,y=0 at t=T, x=uT,y=L
 
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