Understanding the Equation (Gm)/(r-S)^2 = (GM)/r^2

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Homework Help Overview

The discussion revolves around the equation (Gm)/(r-S)^2 = (GM)/r^2, which is related to gravitational forces and distances in a physics context. Participants are attempting to understand the manipulation of this equation and its implications.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand how the transition from (r-S)^2 to S = r - (mr^2)/M is justified. Some participants question the correctness of the original equation and its derivation, while others raise concerns about unit consistency.

Discussion Status

The discussion is ongoing, with participants exploring the validity of the original equation and its implications. Some have pointed out potential errors, leading to a reevaluation of the problem's foundation.

Contextual Notes

There are indications of confusion regarding the units involved in the equation, as well as the correctness of the original formulation. This has led to a questioning of the assumptions made in the problem setup.

highc
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I'm working through a problem that was posted here a while ago (https://www.physicsforums.com/showthread.php?t=115170). maltesers posted the equation (Gm)/(r-S)^2 = (GM)/r^2, so far this makes perfect sense, he then goes on to solve for S with S = r - (mr^2)/M, and it is here that he loses me. How did we eliminate the ^2 to go from (r-S)^2 to S = r - ...?

I've been out of the math game a little too long!
 
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That equation is actually incorrect. It should have been

[tex]\frac{Gm}{(r-S)^2} = \frac{GM}{S^2}[/tex]
 
neutrino said:
That equation is actually incorrect. It should have been

[tex]\frac{Gm}{(r-S)^2} = \frac{GM}{S^2}[/tex]

This not the only thing wrong.

Look at units. In maltesers' last equation, S is a length, while the last term on the right has units of length squared.
 
George Jones said:
This not the only thing wrong.

Look at units. In maltesers' last equation, S is a length, while the last term on the right has units of length squared.
Now that it's known that the original equation is wrong, why bother about what was derived from it. :-p

Thanks for pointing that out.
 
Thanks a lot, I wasted way too much time on this one.
 

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