Understanding the Importance of Particle Reynolds Number in Fluid Dynamics

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The discussion centers on the confusion surrounding the calculation of the particle Reynolds number, particularly why the density and viscosity of the surrounding fluid are used instead of those of the particle itself. It is clarified that the particle Reynolds number applies to all types of particles, including solid particles, liquid droplets, and gas bubbles, with the focus on the fluid's properties because the fluid flows around the particle. The resistance to movement is attributed to fluid deformation, emphasizing that the fluid's characteristics are crucial for determining drag. In scenarios like a liquid droplet falling through air, the droplet is treated as a spherical particle, reinforcing the relevance of the surrounding fluid's properties. Understanding this concept is essential for accurately studying fluid dynamics and the behavior of particles within fluids.
min_ht
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Hello,

The particle Reynolds number makes me confused and I hope someone can help me on this please!

Normally (as I read in every books and papers) that when a bubble or drop rises in a fluid, the bubble/drop Reynolds number is calculated by:

Re = ρUD/μ

where U is particle velocity, D can be particle diameter, and ρ and μ are density and viscosity of continuous fluid

my question is why don't use ρ and μ of bubble/drop? why use them of surrounding fluid?
what is the physical meaning of this Re?

Thanks in advance.
 
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The particle is supposed to be solid, so it has no ##\mu##: the fluid has to move around the particle and not the other way around. :smile:
 
BvU said:
The particle is supposed to be solid, so it has no ##\mu##: the fluid has to move around the particle and not the other way around. :smile:

Thank you for your reply
Actually the term "particle" refers to all solid particle, liquid drop or gas bubble (book: Bubbles, Drops, and Particles of Clift et al. 1978)
just normally people use particle for solid body :)
and that equation for Re applies for all of them
in my case it is liquid droplet, so it has μ, and that's why I don't really understand :(
 
The resistance to the particle movement is caused by the fluid deforming. As reckoned from the frame of reference of particle, the fluid is flowing past. So it is the fluid deformation and flow around the particle that determines the drag on the particle. That's why the focus is on the fluid.
 
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min_ht said:
in my case it is liquid droplet, so it has μ, and that's why I don't really understand

In the case of something like a liquid droplet falling through air, you would make the assumption that the droplet is a spherical particle with no deformation. The Reynolds number still applies to the surrounding fluid flowing around the particle, not the other way around.

https://en.wikipedia.org/wiki/Sediment_transport#Particle_Reynolds_Number
 
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If your goal is to study the flow around a particle, why would you use conditions inside the particle in your study?
 
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Thank you all
I think I got your points and they help a lot
very appreciated!
 
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