- #1
dziech
- 11
- 1
Hi guys,
It's one of the questions I'm asking myself needlessly but I really wonder about this ;)
Say I have a laser at a wavelength λ. I can calculate the frequency by ν=c/λ. Then the linewidth Δν=cΔλ/λ2 that can be found through differentiation of two sides of the equation. The question is, where does the minus go though? It should be Δν=-cΔλ/λ2 should it not? I can't think of what does the negative physically mean here and that's my question.
It's one of the questions I'm asking myself needlessly but I really wonder about this ;)
Say I have a laser at a wavelength λ. I can calculate the frequency by ν=c/λ. Then the linewidth Δν=cΔλ/λ2 that can be found through differentiation of two sides of the equation. The question is, where does the minus go though? It should be Δν=-cΔλ/λ2 should it not? I can't think of what does the negative physically mean here and that's my question.