Understanding the Negative Sign in Laser Linewidth Calculation

  • Context: Undergrad 
  • Thread starter Thread starter dziech
  • Start date Start date
  • Tags Tags
    Calculation Laser
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 4K views
dziech
Messages
10
Reaction score
1
Hi guys,

It's one of the questions I'm asking myself needlessly but I really wonder about this ;)

Say I have a laser at a wavelength λ. I can calculate the frequency by ν=c/λ. Then the linewidth Δν=cΔλ/λ2 that can be found through differentiation of two sides of the equation. The question is, where does the minus go though? It should be Δν=-cΔλ/λ2 should it not? I can't think of what does the negative physically mean here and that's my question.
 
Physics news on Phys.org
Am I just thinking of this the wrong way? I mean, Δν is a linewidth in frequency. Say it's 60GHz, the Δλ should be like 0.2nm at 1um, but it would be -0.2nm wouldn't it? Or should I think of it as Δν change in linewidth? But that doesn't make obvious sense to me. It's one of the questions I should probably not think about too much but my brain keeps doing things to me ;D
 
That clicked! :D I can finally sleep peacefully ;) Thanks!
 
  • Like
Likes   Reactions: BvU