Understanding the Pi-Meson (π0) and its Anti-Particle

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SUMMARY

The discussion centers on the pi-meson (π0) and its behavior in relation to its anti-particle. The π0 is expressed as a superposition of quark states, specifically |π0〉 = 1/√2 (|uu⟩ - |dd⟩), where 'u' represents the anti-up quark and 'd' represents the anti-down quark. Participants clarify that despite being a particle with its own anti-particle, the π0 does not annihilate itself due to its inherent instability and defined half-lives, which govern its decay process.

PREREQUISITES
  • Quantum mechanics fundamentals
  • Understanding of particle physics terminology
  • Knowledge of quark composition and behavior
  • Familiarity with particle decay and half-life concepts
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  • Research the properties of mesons and their decay mechanisms
  • Study the concept of superposition in quantum mechanics
  • Explore the role of quarks in particle physics
  • Learn about the stability and instability of subatomic particles
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Students of particle physics, physicists specializing in quantum mechanics, and anyone interested in the behavior of mesons and their interactions.

Mathilda
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Homework Statement


How does the pi-meson (π0) work without annihilating itself?

Homework Equations


|π01/√2 〉- {|uu − |dd}

u= anti-upquark
d= anti-downquark

The Attempt at a Solution


I do understand that it is a superposition, but why does it work when it is a partice with its own anti.particle?
 
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What do you mean by "work". The pi mesons are all unstable particles which decay with well known half-lives.
 

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