Understanding the Relationship Between Integration and Anti-differentiation

  • Context: Graduate 
  • Thread starter Thread starter Muthumanimaran
  • Start date Start date
  • Tags Tags
    Proof
Click For Summary
SUMMARY

The discussion centers on the proof that integration is equivalent to anti-differentiation, as outlined in "Mathematical Methods for Physics" by Riley and Hobson. The participants clarify that the right-hand side of the equation, after appropriate rearrangement and division by Λx, simplifies to f(x)Λx. They emphasize that the Riemann integral from a to b is defined as the limit of the sum of f(x) multiplied by Δx, leading to the conclusion that the integral from x to x+Δx of f(x)dx represents the upper limit of f(x) multiplied by Δx as Δx approaches zero.

PREREQUISITES
  • Understanding of Riemann integrals
  • Familiarity with anti-differentiation concepts
  • Basic knowledge of limits and continuity
  • Proficiency in mathematical notation and manipulation
NEXT STEPS
  • Study the properties of Riemann integrals in detail
  • Explore the Fundamental Theorem of Calculus
  • Learn about the application of limits in calculus
  • Investigate advanced techniques in anti-differentiation
USEFUL FOR

Students of mathematics, educators teaching calculus, and anyone interested in the foundational concepts of integration and anti-differentiation.

Muthumanimaran
Messages
79
Reaction score
2
While attempting proof for Integration is anti-differentiation from the book Mathematical methods for physics, Riley, Hobson
How the R.H.S of the equation (after rearranging and dividing by Λx) becomes f(x)Λx?
 

Attachments

  • Anti-differentiation rule.jpg
    Anti-differentiation rule.jpg
    33.9 KB · Views: 409
Physics news on Phys.org
Muthumanimaran said:
How the R.H.S of the equation (after rearranging and dividing by Λx) becomes f(x)Λx?
Well, the (Riemann) integral from a to b is defined as the upper limit of \sum_{\bigcup \Delta x = [a, b]}f(x)\cdot\Delta x. So, if you put a=x and b=x+Δx, you get the first element in the sum. Which means that \int_{x}^{x+\Delta x}f(x)dx is the upper limit of f(x)\cdot \Delta x (as Δx→0).
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 19 ·
Replies
19
Views
5K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
9K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 45 ·
2
Replies
45
Views
5K