Why is there a differential in an indefinite integral?

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Jow
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I understand why a definite integral of the form [itex]^{b}_{a}[/itex]∫ƒ(x)dx has the differential dx in it. What I don't understand, and what my teacher hasn't explained is why an indefinite integral (i.e. an antiderivative) requires the differential. Why does ∫ƒ(x)dx require that dx to mean "anti-differentiate"? To put it another way, why is the notation for the antiderivative an integral? It's obviously more than a question of notation, however, as without the differential techniques like u-substitution don't work. I hope this question makes sense, but this is something that has been bothering me for a while now. I figured my teacher would get to it eventually, but he hasn't yet.
 
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Jow said:
To put it another way, why is the notation for the antiderivative an integral?

It's actually the other way around; we use the notation for integrals to talk about antiderivatives. The Fundamental Theorem of Calculus provides a link between the two concepts.

I am not aware of any notation specifically used to talk about antiderivatives, though I propose we begin using ##\frac{d^{-1}}{dx}f## to denote the family of functions whose derivatives are ##f## (which I'm certain will never happen). Most modern textbooks that I'm familiar with either don't have a notation until integration is introduced or they "cheat" and use the usual notation, ##\int f\ dx##, before students learn about integration with little to no explanation for why that is the chosen notation.

In my opinion, referring to antiderivatives as "indefinite integrals" and denoting them by ##\int f\ dx## is an unnecessary abuse of terminology and notation that serves more to confuse students (and some calculus teachers, I'm sure) than it helps them communicate mathematical ideas.