Understanding the Relativistic Doppler Effect in Space Travel

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Homework Help Overview

The discussion revolves around understanding the relativistic Doppler effect as it applies to a scenario involving a rocket traveling from Earth to a space station. Participants are exploring the timing and frequency of light signals transmitted between these entities, considering the effects of relative motion on signal reception and transmission.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are examining how the rocket perceives the timing of signals from Earth and how it retransmits them to the space station. Questions arise regarding the assumptions about signal transmission timing and the implications of relativistic effects on frequency shifts.

Discussion Status

Some participants have provided insights into the relationship between the Doppler effect and the frequency of signals as perceived by the rocket and the space station. There is an acknowledgment of the complexity of the situation, with various interpretations being explored without a clear consensus on the correct approach.

Contextual Notes

There are indications of confusion regarding the assumptions made about signal transmission timing and the relativistic effects involved. Participants are questioning the validity of their calculations and the underlying principles of the Doppler effect in this context.

michael879
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ok this is a rly simple problem I just can't figure it out. There is a rocket traveling from Earth to a space station (which are in the same reference frame). Earth sends light signals at some interval to the rocket, which then sends the signals to the space station. When I work this out I get that the rocket sees the signals coming from Earth as dt*gamma apart where dt is Earth's interval. The rocket then sends the signals at dt*gamma which should be received by the space station at dt*gamma*gamma intervals. I know for a fact this is wrong (and I suspect the first one might be wrong too) since when I draw a space-time diagram of this situation the space station receives the signals at the same speed that Earth sends them and the rocket sends and receives at a higher interval. What am I doing wrong?
 
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michael879 said:
There is a rocket traveling from Earth to a space station (which are in the same reference frame). Earth sends light signals at some interval to the rocket, which then sends the signals to the space station.
Are we to assume that the rocket transmits its signals as soon as it receives the signals from Earth?
When I work this out I get that the rocket sees the signals coming from Earth as dt*gamma apart where dt is Earth's interval.
According to the rocket frame, the Earth transmits signals dt*gamma apart. Now figure out the time interval (according to the rocket) between the arrival of those signals at the rocket.
 
damn, right, thanks a lot man.
 
I'm sorry, maybe I have to study more, but there is something I don't understand: wouldn't this situation be the same as doppler red-shift of light emitted from earth? So the rocket should see the signals arriving to it with a lower frequency, because it is moving away from earth.

When it re-trasmit them immediately to the space-station, the station see them doppler blue-shifted because the rocket is approaching it; so, at the end, signals arrive to the station with exactly the same frequency they are trasmitted from Earth (in the Earth ref. frame):

f(rocket) = f(earth)*SQRT[(c-v)/(c+v)]

f(space-station) = f(rocket)*SQRT[(c+v)/(c-v)] = f(earth)*SQRT[(c-v)/(c+v)]*SQRT[(c+v)/(c-v)] =

= f(earth).

f=frequency
v=rocket's speed
 
Last edited:
lightarrow said:
I'm sorry, maybe I have to study more, but there is something I don't understand: wouldn't this situation be the same as doppler red-shift of light emitted from earth?
Sure it's the same. The observed frequency of incoming signals compared with the source frequency is the Doppler effect. (In solving this problem one essentially derives the relativistic Doppler formula.)
 

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