Understanding the Role of Error Functions in Integrals

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Integrating an expression resulted in an imaginary error function, raising questions about the next steps. The integral was evaluated from -∞ to ∞, prompting a discussion on whether to evaluate the error function at these limits or focus on the root provided by Wolfram. Completing the square in the exponent was suggested as a better approach for handling infinite integrals. The discussion clarified that the integral corresponds to the Fourier transform of a normal curve. Understanding these concepts is crucial for accurately interpreting the results of the integral.
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Okay so I was integrating an expression and ended up getting an imaginary error function in the answer. I'm not sure where to go from there, I plugged it into wolfram and the root it gave me looks nice but is that worth anything to me?

The integral was being evaluated from -∞ to ∞, would I need to evaluate the error function from these limits or is the root what I'm looking for?
 
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Here is the original integral and resulting error function
9-21-2015 9-40-19 PM.jpg
9-21-2015 9-39-38 PM.jpg
 
If you want the infinite integral a better approach is to complete the square (in k) of the exponent. net result is I = e^{\frac{-x^2}{4b}}\sqrt{\frac{\pi}{b}}.

Comment: All you are doing is taking the Fourier transform of a normal curve.
 
Okay that makes sense. Thanks!
 

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