Understanding the Skin Effect: Flux Linkage in a Wire

  • Thread starter Thread starter physiks
  • Start date Start date
  • Tags Tags
    Skin Skin effect
Click For Summary
SUMMARY

The discussion centers on the skin effect and flux linkage in a wire, specifically addressing the misconception that the central filament of a wire links the greatest magnetic flux. Participants clarify that while the magnetic field strength increases linearly outward, the flux linkage for the central filament is actually zero due to the concentric circular nature of the field lines. Consequently, the outer filaments link more flux from external sources, leading to greater self-inductance and impedance at the wire's surface. This understanding is crucial for analyzing current distribution in conductive materials.

PREREQUISITES
  • Understanding of electromagnetic theory, particularly magnetic flux and field lines.
  • Familiarity with the concept of self-inductance in electrical circuits.
  • Knowledge of the skin effect and its implications in conductive materials.
  • Basic principles of wire geometry and cross-sectional analysis.
NEXT STEPS
  • Study the mathematical formulation of the skin effect in cylindrical conductors.
  • Explore the relationship between self-inductance and current distribution in wires.
  • Investigate the impact of wire diameter on impedance and skin depth.
  • Review advanced electromagnetic theory texts focusing on flux linkage and field distribution.
USEFUL FOR

Electrical engineers, physics students, and professionals involved in circuit design and analysis, particularly those interested in the behavior of current in conductive materials.

physiks
Messages
101
Reaction score
0
I'm struggling to understand a key detail about this.

My book divides the cross section of a wire into elementary filaments. It then states that the flux linked by the filament in the centre of the wire will be greatest, then this will decrease until at the outermost filaments the only flux linked is from external sources. This would then mean greater self inductance in the middle of the wire, and thus larger impedance so the current flow is greater towards the surface.

Firstly I know flux linkage refers the the magnetic flux crossing an area. Here the field lines in the wire are concentric circles so when dealing with flux linkage we can't be dealing with the linkage through the cross sectional area of the wire as this would be zero. It must be the flux through the cross section of the wire when viewed from above so the field lines penetrate it.

I'm struggling to understand how the flux linked is greatest in the centre. The wire could be thought of as a series of shells, and the B-field due to the wire increases linearly outwards. The field at the centre of the wire is zero. Therefore surely a central elementary filament links zero flux, and the filaments on the outside link the most flux?
 
Physics news on Phys.org
There is a long thread stickied at the top of the EE forum about this. Maybe have a look at the thread and its related links to see if that helps...
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
17K
  • · Replies 10 ·
Replies
10
Views
5K
Replies
11
Views
4K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 20 ·
Replies
20
Views
5K