Understanding the Standing Wave Equation for Students

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The discussion focuses on the confusion surrounding the standing wave equation, specifically the differences in form between the user's setup and the solution provided. The user correctly identifies the standing wave equation as Y(x,y) = 2YmSin(kx)Cos(wt) but struggles with the negative sign and the switch between sine and cosine in the solution. The explanation clarifies that the form used in the solution is derived from the plot, which indicates that the kx term must be in a cosine function to avoid a flat line at x = 0. Additionally, the sine function for the wt term is necessary to ensure the y value starts at zero and then decreases into negative territory for small positive t. Understanding these adjustments is crucial for accurately representing the standing wave behavior.
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Homework Statement


upload_2015-9-30_6-19-51.png


Homework Equations



y (x,y) = 2YmSin(kx)Cos(wt)

The Attempt at a Solution



I am having trouble at setting up the standing wave equation for this problem.

Once I set up the equation, I know that part a b c d is just plugging in the numbers.

From what I learned, I know that the standing wave equation is

Y(x,y) = 2YmSin(kx)Cos(wt), this is what the textbook states.

(Ym being the amplitude).

I calculated k and w correctly.

The equation I set up was Y(x,y) = .041Sin(kx)Cos(wt)

However, the solution uses the equation

Y(x,y) = -2YmCos(kx)Sin(wt).

therefore,

Y(x,y) = -.041Cos(kx)Sin(wt)

I do not understand why there is a negative sign in front of the amplitude and why Sin and Cos is switched in the equation used by the solution.

Any help or guide will be greatly appreciated, Thank you.
 

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The form used in the solution is based off the plot. The plot at x = 0, with t varying implies that the kx term has to be inside a cosine function--otherwise your plot at x = 0 would be a flat line. The plot shows at t=0, y=0, so the wt term should be inside a sine function. Finally, the y value first dives into negative territory, as t is small and positive, so you would want a negative sine of wt function in order to do that.
 
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