Understanding the Standing Wave Equation for Students

Click For Summary
SUMMARY

The standing wave equation is defined as Y(x,y) = 2YmSin(kx)Cos(wt), where Ym represents the amplitude. In the discussion, the user initially set up the equation correctly but encountered confusion regarding the solution's form, Y(x,y) = -2YmCos(kx)Sin(wt). The negative sign and the switch between sine and cosine functions arise from the behavior of the wave at specific points, particularly at x = 0 and t = 0, which affects the phase of the wave. Understanding these phase shifts is crucial for accurately representing standing waves.

PREREQUISITES
  • Understanding of wave mechanics and standing waves
  • Familiarity with trigonometric functions, specifically sine and cosine
  • Knowledge of wave parameters such as amplitude (Ym), wave number (k), and angular frequency (w)
  • Ability to interpret graphical representations of wave functions
NEXT STEPS
  • Study the derivation of the standing wave equation in detail
  • Learn about phase shifts in wave functions and their implications
  • Explore graphical analysis of wave functions to understand behavior at specific points
  • Investigate the relationship between amplitude, wave number, and frequency in wave mechanics
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as educators seeking to clarify concepts related to standing waves and their mathematical representations.

Voidy
Messages
2
Reaction score
0

Homework Statement


upload_2015-9-30_6-19-51.png


Homework Equations



y (x,y) = 2YmSin(kx)Cos(wt)

The Attempt at a Solution



I am having trouble at setting up the standing wave equation for this problem.

Once I set up the equation, I know that part a b c d is just plugging in the numbers.

From what I learned, I know that the standing wave equation is

Y(x,y) = 2YmSin(kx)Cos(wt), this is what the textbook states.

(Ym being the amplitude).

I calculated k and w correctly.

The equation I set up was Y(x,y) = .041Sin(kx)Cos(wt)

However, the solution uses the equation

Y(x,y) = -2YmCos(kx)Sin(wt).

therefore,

Y(x,y) = -.041Cos(kx)Sin(wt)

I do not understand why there is a negative sign in front of the amplitude and why Sin and Cos is switched in the equation used by the solution.

Any help or guide will be greatly appreciated, Thank you.
 

Attachments

  • upload_2015-9-30_6-19-35.png
    upload_2015-9-30_6-19-35.png
    8.1 KB · Views: 548
Physics news on Phys.org
The form used in the solution is based off the plot. The plot at x = 0, with t varying implies that the kx term has to be inside a cosine function--otherwise your plot at x = 0 would be a flat line. The plot shows at t=0, y=0, so the wt term should be inside a sine function. Finally, the y value first dives into negative territory, as t is small and positive, so you would want a negative sine of wt function in order to do that.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
8K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
27
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K