Understanding the Two Types of Density Operators in Quantum Mechanics

Liao Chen
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I'm confused about the two density operators:

\rho=\sum_{i}\delta(r-r_{i}) and \rho=\sum_{i}|\psi_{i}>\rho_{ii}<\psi_{i}|

Is there anyone explaining this question to me? Thanks very much.
 
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The first one is not normalized if your sum has more than one term.
 
arkajad said:
The first one is not normalized if your sum has more than one term.

Thanks a lot. Do you mean the two density operators are the same and connected through some transformations? Could you explain with a little more details?
 
After some thinking I really do not know what the first expression could mean. It does not make any sense to me. If I consider it as an operator, it would act as

(\rho\psi)(x&#039;)=\int \delta(x-x_i)\psi(x)dx=\sum_i\psi(x_i)

which is a number and not a function. For a continuous spectrum the formula should look like

(\rho\psi)(x&#039;)=\int \rho(x&#039;,x)\psi(x)dx

So, where did you get it from?
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

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