MHB Understanding Two Graph Theory Problems

Puzzles
Messages
21
Reaction score
0
Hi!

I'm struggling with these two problems:

1. If for whichever two vertices a and b in the graph G there is only one simple path from a to b, then the graph is a tree.

Eh... isn't this part of the definition for a tree? I really don't even know where to start with proving this statements.

2. Find which complete bipartite graphs are complete.

What does it mean which COMPLETE bipartite graphs are complete? Can a complete bipartite graph not be complete?

Any help is very much appreciated!
 
Physics news on Phys.org
There are several equivalent definitions of a tree. Some of them are:
  1. A connected acyclic graph.
  2. A graph where every two vertices are connected by a single simple path.
  3. A connected graph where every edge is a bridge (i.e., its removal makes the graph disconnected).
  4. A connected graph with $n$ vertices and $n-1$ edges.
  5. An acyclic graph with $n$ vertices and $n-1$ edges.

Concerning the second problem, a complete graph $K_n$ on $n$ vertices is a graph that has an edge between every pair of vertices. So I think the question means, for which $m$ and $n$ the complete bipartite graph $K_{m,n}$ is also $K_{m+n}$. The answer probably depends on whether $m$ and $n$ in $K_{m,n}$ can be zero.
 
Namaste & G'day Postulate: A strongly-knit team wins on average over a less knit one Fundamentals: - Two teams face off with 4 players each - A polo team consists of players that each have assigned to them a measure of their ability (called a "Handicap" - 10 is highest, -2 lowest) I attempted to measure close-knitness of a team in terms of standard deviation (SD) of handicaps of the players. Failure: It turns out that, more often than, a team with a higher SD wins. In my language, that...
Hi all, I've been a roulette player for more than 10 years (although I took time off here and there) and it's only now that I'm trying to understand the physics of the game. Basically my strategy in roulette is to divide the wheel roughly into two halves (let's call them A and B). My theory is that in roulette there will invariably be variance. In other words, if A comes up 5 times in a row, B will be due to come up soon. However I have been proven wrong many times, and I have seen some...

Similar threads

Replies
1
Views
7K
Replies
1
Views
2K
Replies
2
Views
2K
Replies
1
Views
1K
Replies
1
Views
2K
Replies
2
Views
3K
Replies
1
Views
1K
Replies
1
Views
2K
Back
Top