Understanding vectors and gibberish

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Homework Help Overview

The discussion revolves around finding position vectors for points on the line defined by the equation y=2x+4, specifically points that are a certain distance from the origin in different quadrants. The original poster expresses difficulty in understanding the problem and seeks clarification on how to approach it.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants suggest drawing the graph of the line and a circle to visualize the problem. They discuss using the Pythagorean theorem to find distances and the relationship between the coordinates of points on the line and their distances from the origin. There is also mention of notation related to vectors and matrix forms.

Discussion Status

The conversation is ongoing, with participants providing guidance on how to visualize the problem and suggesting methods to find the intersection points of the line and the circle. The original poster has expressed some understanding but continues to seek clarity on the next steps.

Contextual Notes

The original poster notes their background and current challenges with studying, which may affect their understanding of the problem. There is an emphasis on the need to clarify the setup and assumptions regarding the distances and quadrants involved.

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Homework Statement



For the line y=2x+4

A, find the posiotion vector of the point A, on the line, Which is 6 units from the origin in the 1st quadrant. Express your answer in:

i.] Matrix form. [Never done matrix]

ii.] the form OA [Line with arrow pointing right above it.] = xi +yj

B, Find the position vector for the point B on the line, which is 12 units from the origin in the 3rd quadrant. Express your answer in,

i.] Matrix

ii.] the form OB [Line above it facing right.]

C, Find the cordinates of the mid point of AB.

d, what is the vector equation of the line y=2x+4 in parametric form?

The Attempt at a Solution



Now I know I am nearly 19. Finished school 2 years ago and am now working a 5am-5pm job manuel not pen pushing an just find it hard to study and remeber when I am working.
So forgive me for F%%$ing up.

Right apart from just drawing the graph of y=2x+4 that is all I get.
I think they are meaning to add a point 6 units from the 0 middle point on graph. But not sure.

Which would give me a rectangle. Point starting from -2,0 0,6 14,6. That is if I have done it right. I have done it x,y. That they right way around.

What on Earth do I do from here if I am right?

Cheers,

mac
 
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Venito said:

Homework Statement



For the line y=2x+4

A, find the posiotion vector of the point A, on the line, Which is 6 units from the origin in the 1st quadrant. Express your answer in:

i.] Matrix form. [Never done matrix]

ii.] the form OA [Line with arrow pointing right above it.] = xi +yj

B, Find the position vector for the point B on the line, which is 12 units from the origin in the 3rd quadrant. Express your answer in,

i.] Matrix

ii.] the form OB [Line above it facing right.]

C, Find the cordinates of the mid point of AB.

d, what is the vector equation of the line y=2x+4 in parametric form?

The Attempt at a Solution



Now I know I am nearly 19. Finished school 2 years ago and am now working a 5am-5pm job manuel not pen pushing an just find it hard to study and remeber when I am working.
So forgive me for F%%$ing up.

Right apart from just drawing the graph of y=2x+4 that is all I get.
I think they are meaning to add a point 6 units from the 0 middle point on graph. But not sure.

Which would give me a rectangle. Point starting from -2,0 0,6 14,6. That is if I have done it right. I have done it x,y. That they right way around.

What on Earth do I do from here if I am right?

Cheers,

mac

First off it might make it easier to graph y = 2x + 4.

A. 6 units is the distance from the origin (0,0) to the point. So if you drew a straight line from (0,0) to the point A the length of that would = 6. That distance can be found using the Pythagorean theorem. Just draw a dot at a random point in the first quadrant (top right) and draw a line from the origin to it. Then make a right triangle. You will see the sides of the triangle are of size x and y. Then use Pythagorean theorem to get the distance.

I think the two parts is just notation. The line above the OB means it is a vector [tex]\vec{OB}[/tex] Once you solve for x and y from Pythagorean put those into xi +yj and leave the i and j there. The i and j just mean they are vectors going in the x and y directions respectively. i stands for the x direction and j stands for the y direction. For matrix form either [tex] <br /> \left(<br /> \begin{array}{cc}<br /> x & y<br /> \end{array}<br /> \right)<br /> <br /> \left(<br /> \begin{array}{cc}<br /> x\\<br /> y <br /> \end{array}<br /> \right)[/tex]
either one for whatever your x and y values are.
 
so let's start with A i.)

first, always start by drawing a picture

Now draw the line y=2x+4
Then draw a circle of radius 6, with centre (0,0)
You're looking for where the line and circle intersect.
There will be 2 intersection points.
The question asks for the first quandrant, that is just the upper right section of the coordinate axes where both x & y are positive.

You can solve for this by writing the equation of a circle of radius 6
[tex]x^2 + y^2 = 6^2[/tex]

use the equation of a line to substitute in and solve for x or y
if you find the solution is:
x=a, y = b
i) then in matrix form it will be (a,b) (or vertically with a & b on top of each other)
ii) write the same numbers as ai+bj
 
Last edited:
Thank you all very much. That makes much clearer sence.

mac
 

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