- #1
oso0690
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Homework Statement
I want to understand what happens to exp((6-s)t) when t goes to infinity. Btw, this is part of a Laplace Transform so that's what the 's' is.
Homework Equations
f(t) = exp(6t)u(t)
Find Laplace Transform.
The Attempt at a Solution
I get to:
exp((6-s)t) / (6-s) in which i must integrate from 0 to infinity. I'm pretty sure the answer is 1 / (6-s) but I don't understand why. Breaking apart exp(6t) goes to infinity. And breaking apart exp(-st) goes to 0 right? *when t=inf