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Uniform Circular motion, angular velocity and Friction

  1. Mar 18, 2009 #1
    1. The problem statement, all variables and given/known data
    A 7.00 g coin is placed 17.0 cm from the center of a turntable. The coin has static and kinetic coefficients of friction with the turntable surface of [tex]\mu[/tex]s = 0.850 and [tex]\mu[/tex]k = 0.540

    What is the maximum angular velocity with which the turntable can spin without the coin sliding?



    2. Relevant equations

    a=m(V^2)/r

    3. The attempt at a solution

    I will assume that the weight and the normal force cancel each other out, so I am only dealing with the forces on the horizontal plane.

    Normal force = weight = m*g = (.007g*9.8)= .0686N

    I find the force of the static friction and the kinetic friction.
    F[tex]_{s}[/tex]=[tex]\mu[/tex]*n=(.850*.0686)=.05831
    F[tex]_{k}[/tex]=[tex]\mu[/tex]*n=(.540*.0686)=.037044

    This is where I start thinking. As long as the static friction is greater than the kinetic the coin will keep its current velocity, which is zero.
    So for the coin to move the kinetic friction would have to be greater than the static friction (right???)

    What I assume I will do is use F=ma to find the velocity of the turntable.

    So I set up the problem as:
    Kinetic Friction - Static Friction = m*(v^2/r)

    But I seem to be stuck right there because I am not sure how to get from the velocity to the angular velocity, as the angular velocity is the ratio in the change of the angle divided by the change in time.

    Did I do the above steps correctly, and is my thinking correct as well? If so, how do I get to the angular velocity in rad/s?
    I feel like there is some info missing from the problem
     
  2. jcsd
  3. Mar 19, 2009 #2

    alphysicist

    User Avatar
    Homework Helper

    Hi Patty-o,

    No; the formula you have for the static friction should be:

    [tex]
    f_{s,{\rm max}}=\mu_s N
    [/tex]

    or

    [tex]
    f_s \le \mu_s N
    [/tex]

    because it tells you the maximum value of the static friction. You can calculate how much frictional force is required to hold the coin in place; if the required amount is greater than the static frictional force can provide then it will slip (and once it is slipping then you would start using your kinetic frictional force formula to find the friction).


    So for this equation, you would use either kinetic friction or static friction (but not both), making your choice based on whether the coin is slipping or not.

    Here is an webpage on angular quantities and relating angular and linear quantities:

    http://hyperphysics.phy-astr.gsu.edu/HBASE/rotq.html

     
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