Uniform Circular Motion Bicycle Tire

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SUMMARY

The discussion focuses on calculating the angle of rotation for a bicycle tire with a radius of 0.33m after a paint spot travels a linear distance of 1.66m. The relevant equations include the relationship between linear distance and angular displacement, specifically \( s = r\theta \). The solution involves rearranging the equation to find the angle \( \theta \) in radians, confirming that the problem does not require time-based calculations.

PREREQUISITES
  • Understanding of uniform circular motion concepts
  • Familiarity with angular displacement and its relationship to linear distance
  • Knowledge of the equations \( s = r\theta \) and \( v = r\omega \)
  • Basic algebra for rearranging equations
NEXT STEPS
  • Study the derivation and application of the equation \( s = r\theta \)
  • Learn about angular velocity and its calculation using \( v = r\omega \)
  • Explore the concept of period \( T \) in circular motion
  • Investigate practical applications of uniform circular motion in real-world scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to explain these concepts effectively.

eagles12
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Homework Statement



A spot of paint on a bicycle tire moves in a circular path of radius .33m. When the spot has traveled a linear distance of 1.66m, through what angle has the tire rotated?

Homework Equations



v=rw
w=2∏/T


The Attempt at a Solution



1.66=2∏/T
1.66T=2∏
100∏/83
 
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hi eagles12! :smile:
eagles12 said:
A spot of paint on a bicycle tire moves in a circular path of radius .33m. When the spot has traveled a linear distance of 1.66m, through what angle has the tire rotated?

v=rw
w=2∏/T

T is the period (a time) …

this question has nothing to do with time :wink:

in adition to v = rω, you also need to learn …

s = rθ

a = rα :smile:
 

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