Uniform linear splines is my equation correct?

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Homework Help Overview

The discussion revolves around the definition and translation of uniform linear splines, specifically focusing on the function Hk defined in terms of H0. Participants are examining the correctness of the transformation applied to H0 when calculating H−1.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are exploring the correct translation of the spline function H0 to derive H−1. Questions arise about the proper application of the transformation and the interpretation of the inequalities involved.

Discussion Status

There is an ongoing examination of the definitions and transformations, with some participants clarifying misunderstandings about the translation process. Guidance has been offered regarding the correct approach to defining H−1 based on H0.

Contextual Notes

Some participants express confusion over the application of the function definitions and the implications of translating the splines. There is a mention of an accidental error in the initial function definition that may have contributed to the misunderstanding.

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The question as stated: Define the uniform linear splines Hk:=H0(x−k), k=−1,0,1,2,3, where

H0={x, 0≤x<1,

2−x, 1≤x<2,

0, otherwise.

For k=−1, I would get:

H−1={x+1, 1≤x<2,

1−x, 2≤x<3,

0, otherwise.

Is that correct?

Thank you.
 
Last edited:
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No. ##H_{-1}## would be ##H_0## translated one unit to the left. You moved it to the right.
 
H−1(x)=H0(x+1), right?
H0(x)={x+1, 0≤x<1,
2−x, 1≤x<2,
0, otherwise}​
To get H0(x+1), wouldn't you write x+1 for x everywhere in the definition of H0(x)?
 
LCKurtz-Wouldn't I just plug in k=-1, into H_0(x-(-1))=H_0(x+1)?
 
haruspex-

I accidently put x+1 for the first function in H0, it's supposed to be x.

Yes, I see what you mean. I thought I did that though:
H−1={x+1, 1≤x<2,

1−x, 2≤x<3,

0, otherwise.

I don't see what I'm doing wrong...
 
No, you should have got:
H0(x+1)={x+1, 0≤x+1<1,
1−x, 1≤x+1<2,​
 
Oh okay, I see what you mean. I though I could evaluate it at the inequalities. Thanks!
 

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