Uniform Motion Review - Boat travelling

Click For Summary
SUMMARY

The discussion focuses on a physics problem involving a boat's displacement and distance traveled. The boat has a horizontal displacement of 750 m [E] and a total distance of 1100 m. Using the Pythagorean theorem, the vertical displacement is calculated to be 805 m [N], leading to a resultant direction of [E 47 N]. Participants clarify the distinction between distance and displacement, emphasizing that they are not interchangeable due to displacement being a vector quantity.

PREREQUISITES
  • Understanding of vector quantities in physics
  • Knowledge of the Pythagorean theorem
  • Familiarity with trigonometric functions, specifically cosine
  • Basic concepts of displacement and distance in motion
NEXT STEPS
  • Study vector decomposition in physics
  • Learn about the applications of the Pythagorean theorem in real-world scenarios
  • Explore trigonometric functions and their applications in navigation
  • Research the differences between scalar and vector quantities
USEFUL FOR

Students studying physics, educators teaching motion concepts, and anyone interested in understanding vector analysis in navigation scenarios.

anneku
Messages
4
Reaction score
0
Homework Statement
A boat travelling close to the coast is heading in
an unknown direction. The captain contacts an
observer on the shore to help her determine the
direction the boat is heading. The observer on the
shore reports that the horizontal displacement of the
boat is 750 m [E] and that the boat travelled north
an unknown distance. The captain has measured a
total distance of 1100 m that the boat moved. How far
north did the boat travel and in what direction is the
boat travelling?
Relevant Equations
total displacement = change in position on x axis + change in position on y axis
displacement (x) = 750 m [E]
distance = 1100 m

I drew a diagram. Now what??
 
Physics news on Phys.org
anneku said:
Homework Statement: A boat traveling close to the coast is heading in
an unknown direction. The captain contacts an
observer on the shore to help her determine the
direction the boat is heading. The observer on the
shore reports that the horizontal displacement of the
boat is 750 m [E] and that the boat traveled north
an unknown distance. The captain has measured a
total distance of 1100 m that the boat moved. How far
north did the boat travel and in what direction is the
boat travelling?
Homework Equations: total displacement = change in position on x-axis + change in position on y axis

displacement (x) = 750 m [E]
distance = 1100 m

I drew a diagram. Now what??
Show your work. You have the wrong answer.
 
phinds said:
Show your work. You have the wrong answer.

I got the correct answer as the displacement on the y-axis is 805 m [N] as this is a right-angled triangle (using Pythagorean theorem). The boat is also traveling [ E 47 N ] as cosΘ =750/1100 and therefore the angle would be 47°.

Why would the length of the hypotenuse be 1100 m though? 1100m is distance. It would be wrong to assume that the distance and displacement are the same.
 
phinds said:
Show your work. You have the wrong answer.
Anneku did not quote an answer, merely restated the given data.
 
anneku said:
Why would the length of the hypotenuse be 1100 m though? 1100m is distance. It would be wrong to assume that the distance and displacement are the same.
It does not say they are the same, and they cannot be because displacement is a vector.
There is an assumption that the direction is constant, so the distance traveled is the magnitude of the displacement.
 
haruspex said:
Anneku did not quote an answer, merely restated the given data.
Ah. You're right. I missed that (obviously).
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
Replies
25
Views
3K
Replies
7
Views
2K
Replies
31
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K