Uniform rod resting against rough vertical wall supported by a string.

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SUMMARY

The discussion focuses on a physics problem involving a uniform rod AB, 2 meters long and weighing 3 kg, resting against a rough vertical wall with a coefficient of friction μ. The rod is in limiting equilibrium, supported by a light inextensible string attached to point C on the wall, 2 meters above point B, forming an angle of 120° at ABC. By taking moments about point C, the normal reaction at point B is calculated to be approximately 12.7 N, and the value of μ needs to be determined based on the forces acting on the rod.

PREREQUISITES
  • Understanding of static equilibrium and forces
  • Knowledge of moments and torque calculations
  • Familiarity with friction concepts and coefficients
  • Ability to interpret and create free-body diagrams
NEXT STEPS
  • Study the principles of static equilibrium in physics
  • Learn about calculating moments and their applications in mechanics
  • Research the effects of friction on inclined surfaces and objects in equilibrium
  • Practice drawing and analyzing free-body diagrams for various scenarios
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone studying mechanics, particularly those focusing on static equilibrium and friction in rigid body systems.

kozor
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Homework Statement


Uniform rod AB with end B resting against rough vertical wall. Coefficient of friction between wall and rod is μ.

Rod is 2m long and has mass 3kg.

Rod is kept in limiting equilibrium by a light inextensible string, one end of which is attached to the end A of the rod and the other to point C on the wall 2m above B. Angle ABC=120°.

The end B of the rod is about to slip down the wall.

1. By taking moments about C, show that the normal reaction at B is approx. 12.7N.

2. Find the value of μ.PS: A labelled diagram would be very helpful! Thanks!

Homework Equations


n/a

The Attempt at a Solution



Have been able to sketch what I think are all the forces acting on the rod, but does the normal reaction + friction + T-resolved = downward force of 2g-resolved? Do I take the weight of the rod to act from the centre?
 
Last edited:
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kozor said:
PS: A labelled diagram would be very helpful! Thanks!
Yes, it would! Can you provide one?
 
No worries.

http://imageshack.com/a/img836/6874/gykt.png
 
Last edited by a moderator:
Yes, unless otherwise stated, its safe assume the rod is uniform in which case its center of gravity is at the center
 

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