Uniformly Bounded Functions: Proving Sequence Convergence

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The discussion centers on proving that a sequence of uniformly convergent bounded functions is uniformly bounded. The proof begins with the observation that each function in the sequence, denoted as ||fn||, is bounded by a constant Mn. The discussion highlights that for functions beyond a certain index N, the maximum of the bounds M1...MN+1 serves as a uniform bound. Additionally, the second part of the discussion involves demonstrating the boundedness of the function fp defined in a metric space, utilizing the triangle inequality to establish the relationship between distances.

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chaotixmonjuish
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Prove that a sequence of uniformly convergent bounded functions is uniformly bounded.

Attempt at proof:

So first we observe the following: ||fn||\leqMn. Each function is bounded. Also, |fn-f|\leq\epsilon for all n \geq N. First off, we observe that for finitely many fn's, we have them bounded by M1...MN. Then for n\geq N MN+1 acts as a bound.

So now we make a new M = max{M1...MN+1}.

I'm kind of stuck on how to demonstrate uniform boundedness with an inequality.

My second question is as follows:

Let X be a metric space with a metric d. Let a be a fixed point in X. Let p be a point in X. Define fp=d(x,p)-d(x,a).

I want to show this is bounded.

For this one I have no idea.
 
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The second one follows directly from the "triangle inequality": d(x,p)\le d(x,a)+ d(a,p)
 

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