chaotixmonjuish
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Prove that a sequence of uniformly convergent bounded functions is uniformly bounded.
Attempt at proof:
So first we observe the following: ||fn||[tex]\leq[/tex]Mn. Each function is bounded. Also, |fn-f|[tex]\leq[/tex][tex]\epsilon[/tex] for all n [tex]\geq[/tex] N. First off, we observe that for finitely many fn's, we have them bounded by M1...MN. Then for n[tex]\geq[/tex] N MN+1 acts as a bound.
So now we make a new M = max{M1...MN+1}.
I'm kind of stuck on how to demonstrate uniform boundedness with an inequality.
My second question is as follows:
Let X be a metric space with a metric d. Let a be a fixed point in X. Let p be a point in X. Define fp=d(x,p)-d(x,a).
I want to show this is bounded.
For this one I have no idea.
Attempt at proof:
So first we observe the following: ||fn||[tex]\leq[/tex]Mn. Each function is bounded. Also, |fn-f|[tex]\leq[/tex][tex]\epsilon[/tex] for all n [tex]\geq[/tex] N. First off, we observe that for finitely many fn's, we have them bounded by M1...MN. Then for n[tex]\geq[/tex] N MN+1 acts as a bound.
So now we make a new M = max{M1...MN+1}.
I'm kind of stuck on how to demonstrate uniform boundedness with an inequality.
My second question is as follows:
Let X be a metric space with a metric d. Let a be a fixed point in X. Let p be a point in X. Define fp=d(x,p)-d(x,a).
I want to show this is bounded.
For this one I have no idea.
Last edited: