Unifying Orders in Finite Group Conjugacy Classes

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SUMMARY

The discussion centers on proving that all elements within a conjugacy class of a finite group share the same order. It defines a conjugacy class as cl(a) = {xax^-1 | x in G}, where G is a finite group represented as G = {e, g1, g2, ..., gm}. The elements of the conjugacy class, such as cl(g) = {e, c1, c2, c3, ..., cn}, are finite and have orders that are equal, denoted as |e| = |c1| = |c2| = ... = |cn|. The discussion emphasizes the importance of understanding the definition of the order of an element in this context.

PREREQUISITES
  • Understanding of finite group theory
  • Familiarity with the concept of conjugacy classes
  • Knowledge of the definition of the order of an element in group theory
  • Basic grasp of group operations and properties
NEXT STEPS
  • Study the properties of finite groups and their conjugacy classes
  • Learn about the definition and implications of the order of an element in group theory
  • Explore the relationship between conjugacy class sizes and group orders
  • Investigate examples of finite groups and their conjugacy classes
USEFUL FOR

Mathematicians, particularly those specializing in abstract algebra, students studying group theory, and anyone interested in the properties of finite groups and their conjugacy classes.

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Show that the
elements in a conujgacy class of a
finite group all have the same order

cl(a) = {xax^-1|x in G} G is finite
G = {e,g1,g2,...,gm}

cl(g)={e,c1,c2,c3,...,cn} finite for n =< m

Then |e| | n , |c1| | n, |c2| | n, |cn| | n


Well C1 =xgix^1 for some gi.

any hint?
 
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What is the definition of order of an element? And I don't mean for you to just post it here, I mean for you to go from that and think about things: if x^n=e what can you say about n relative to the order of e?
(That the conjugacy class sizes divide the order of the group is immaterial.)
 

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