Unit conversions involving Pascals

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A discussion on unit conversions involving Pascals highlighted the relationship between different pressure units, specifically how to convert Newtons per square meter (N/m²) into Pascals (Pa) and kilopascals (kPa). Participants clarified that 1 Pa equals 1 N/m² and provided examples of converting large values, such as 15,625,000 N/m² to 15,625 kPa. The conversation also touched on the importance of using correct units and significant figures in calculations, particularly when dealing with areas and constants like π. Misunderstandings about negative exponents and unit conversions were addressed, emphasizing the need for clarity in mathematical expressions. Overall, the thread served as a learning platform for those grappling with unit conversions and foundational concepts in physics.
  • #61
jbriggs444 said:
Online converters work. Just have to use the right units. I Googled "convert square millimeters to square meters". Without leaving the Google page, a converter was displayed. I keyed in 1963.5.
View attachment 255555

Good nit saying that it s an area value it was a mistake
 
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  • #62
A.T. said:
Use the one for which you have the required variables.

Yeah and is it that you multiply first or work the division separated and the multiply the results ?
 
  • #63
chriscarson said:
Yeah and is it that you multiply first or work the division separated and the multiply the results ?
Multiply what by what or work what division? Are you seriously asking how to evaluate ##\frac{a}{b} \times \frac{c}{d}##?
 
  • #64
jbriggs444 said:
Multiply what by what or work what division? Are you seriously asking how to evaluate ##\frac{a}{b} \times \frac{c}{d}##?

Yes is that so basic ?
 
  • #65
chriscarson said:
Yes is that so basic ?
Here in the U.S. we are taught to add and multiply fractions at about age eight.

For ##\frac{a}{b} \times \frac{c}{d}## there are many ways to evaluate the result and get the same right answer. The canonical "right" way is to:

1. Divide a by b giving the result ##\frac{a}{b}##.
2. Divide c by d giving the result ##\frac{c}{d}##.
3. Multiply those two results together.

Another way is to:

1. Multiply a by c giving the result ##ac##.
2. Multiply b by d giving the result ##bd##.
3. Divide the result from 1) by the result from 2).

It is a rule of arithmetic and of real algebra that$$\frac{a}{b} \times \frac{c}{d} = \frac{ac}{bd}$$

One rule of algebra that they didn't teach us until age 16 or so was that putting two variable names side by side ("juxtaposition") is a notation that conventionally means "multiply them together".

[As it turns out my first exposure to the juxtaposition notation was in a standardized test -- they tested on it before my school had ever presented the content. It is over 40 years later now and that incident still cheeses me off]
 
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  • #66
jbriggs444 said:
Here in the U.S. we are taught to add and multiply fractions at about age eight.

For ##\frac{a}{b} \times \frac{c}{d}## there are many ways to evaluate the result and get the same right answer. The canonical "right" way is to:

1. Divide a by b giving the result ##\frac{a}{b}##.
2. Divide c by d giving the result ##\frac{c}{d}##.
3. Multiply those two results together.

Another way is to:

1. Multiply a by c giving the result ##ac##.
2. Multiply b by d giving the result ##bd##.
3. Divide the result from 1) by the result from 2).

It is a rule of arithmetic and of real algebra that$$\frac{a}{b} \times \frac{c}{d} = \frac{ac}{bd}$$

One rule of algebra that they didn't teach us until age 16 or so was that putting two variable names side by side ("juxtaposition") is a notation that conventionally means "multiply them together".

[As it turns out my first exposure to the juxtaposition notation was in a standardized test -- they tested on it before my school had ever presented the content. It is over 40 years later now and that incident still cheeses me off]

Yeah finally is that what I thought but I m finding so many obstacles that I want to be 100% in every tiny thing .
 
  • #68

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