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Unit conversions involving Pascals

  • #1
Thread moved from a technical forum
Summary:: Pascal units digits

Do somebody have a chart that converts pascals , mega pascals etc to units to know how many digits or zeros there are after the point please ?

Thanks
 

Answers and Replies

  • #2
Vanadium 50
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Theres' nothing special about pascals. Kilo is 1000, mega is 1000000 etc.
 
  • #3
So for example when you have the result of 15 625 000 N m 2 how you put in pascals ? 15 625 kPa ?

Thanks
 
  • #4
etotheipi
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So for example when you have the result of 15 625 000 N m 2 how you put in pascals ? 15 625 kPa ?

Thanks
Yes, ##1 \text{ Pa} = 1 \text{ N} \text{m}^{-2}## by definition. Like @Vanadium 50 alluded to, the SI prefixes are general.
 
Last edited:
  • #7
Yes, ##1 Pa = 1 Nm^{-2}## by definition. Like @Vanadium 50 alluded to, the SI prefixes are general.
So 1 Pa = 0.01Nm with tha little -2 ?
 
  • #8
etotheipi
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So 1 Pa = 0.01Nm with tha little -2 ?
No, ##\text{N} \text{m}^{-2}## is equivalent to ##\frac{\text{N}}{\text{m}^{2}}##! It has no relevance to the prefix whatsoever!
 
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  • #9
No, ##Nm^{-2}## is equivalent to ##N/m^{2}##! It has no relevance to the prefix whatsoever!

Ok
Thanks . Have to study more about these to understand.
 
  • #10
etotheipi
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So for example when you have the result of 15 625 000 N m 2 how you put in pascals ? 15 625 kPa ?

Thanks
You seemed like you had it here! You can think of units sort of like algebraic quantities. To do the conversion, you could write down

##15625000 \text{ N}\text{m}^{-2} = 15625 \times 10^{3} \text{ N}\text{m}^{-2} = 15625 \text{ kN}\text{m}^{-2} = 15625 \text{ kPa}##

just like you obtained. Once you get the hang of it, you'll find that you won't really need to think at all/write all of that junk out!
 
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  • #11
You seemed like you had it here! You can think of units sort of like algebraic quantities. To do the conversion, you could write down

##15625000 Nm^{-2} = 15625 \times 10^{3} Nm^{-2} = 15625 kNm^{-2} = 15625 kPa##

just like you obtained. Once you get the hang of it, you'll find that you won't really need to think at all/write all of that junk out!
I notice you made always a -2 on the m .
 
  • #12
Mister T
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I notice you made always a -2 on the m .
##m^{-2}=\frac{1}{m^2}##
 
  • #13
##m^{-2}=\frac{1}{m^2}##
It s ok I give up . But thanks anyway for your help .
 
  • #14
vanhees71
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You seemed like you had it here! You can think of units sort of like algebraic quantities. To do the conversion, you could write down

##15625000 Nm^{-2} = 15625 \times 10^{3} Nm^{-2} = 15625 kNm^{-2} = 15625 kPa##

just like you obtained. Once you get the hang of it, you'll find that you won't really need to think at all/write all of that junk out!
And it's very important to typeset units in roman (upright), it should read
$$1 \, \text{Pa}=1 \, \text{N} \, \text{m}^{-2}=1 \, \frac{\text{N}}{\text{m}^2}$$
etc.
 
  • #15
etotheipi
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And it's very important to typeset units in roman (upright), it should read
$$1 \, \text{Pa}=1 \, \text{N} \, \text{m}^{-2}=1 \, \frac{\text{N}}{\text{m}^2}$$
etc.
Ah that's useful, never knew \text{} was a thing! My latex is dreadful...
 
  • #16
jtbell
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##m^{-2}=\frac{1}{m^2}##
It s ok I give up . But thanks anyway for your help .
Have you never seen negative exponents used to indicate reciprocals? $$10^{-2}=\frac 1 {10^2} = \frac 1 {100}$$ $$x^{-3} = \frac 1 {x^3}$$ etc.
 
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  • #17
Have you never seen negative exponents used to indicate reciprocals? $$10^{-2}=\frac 1 {10^2} = \frac 1 {100}$$ $$x^{-3} = \frac 1 {x^3}$$ etc.

No . I finished school early now I m taking a course .
 
  • #18
jbriggs444
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No . I finished school early now I m taking a course .
The meaning for negative exponents follows naturally from the law of exponents:$$x^{a+b}=x^a \times x^b$$
If you have an exponent ##-a##, it then follows that:$$x^{-a} \times x^a = x^{-a+a} = x^0$$ By definition(*), ##x^0=1## so we can write: $$x^{-a} \times x^a = 1$$ If we divide through by ##x^a## that yields: $$x^{-a} = \frac{1}{x^a}$$

(*) One might quibble about the grounding definitions for exponentiation. But I like to start with the idea that an empty product yields the multiplicative identity (1) just like an empty sum yields the additive identity (0).
 
  • #19
The meaning for negative exponents follows naturally from the law of exponents:$$x^{a+b}=x^a \times x^b$$
If you have an exponent ##-a##, it then follows that:$$x^{-a} \times x^a = x^{-a+a} = x^0$$ By definition(*), ##x^0=1## so we can write: $$x^{-a} \times x^a = 1$$ If we divide through by ##x^a## that yields: $$x^{-a} = \frac{1}{x^a}$$

(*) One might quibble about the grounding definitions for exponentiation. But I like to start with the idea that an empty product yields the multiplicative identity (1) just like an empty sum yields the additive identity (0).

I will need a very basic lesson to understand this . I started from the middle of the subject. but thanks
 
  • #20
jbriggs444
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I will need a very basic lesson to understand this . I started from the middle of the subject. but thanks
You could start with Wiki. Though a textbook might be better.
 
  • #21
You could start with Wiki. Though a textbook might be better.

I will but I m focusing on what the exams will be about and we stopped to work out stress , strain, and young modulus because it s an assistant technician course.
 
  • #22
Mister T
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So for example when you have the result of 15 625 000 N m 2 how you put in pascals ? 15 625 kPa ?
First of all it would be 15 625 000 N/m². That's 15 625 000 newtons of force on each square meter of area. This would be, by definition, 15 625 000 Pa. And since there are 1000 pascals in a kilopascal, it would be equivalent to 15 625 kPa.
 
  • #23
this one it s ok i fully understood it
 
  • #24
Vanadium 50
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I will but I m focusing on what the exams will be about and we stopped to work out stress , strain, and young modulus because it s an assistant technician course.
Yes, but they will expect you to understand unit prefixes and exponents. What you are learning builds upon them. Knowledge is cumulative. If you have a gap, it will come up again and again until it's filled.
 
  • #25
Yes, but they will expect you to understand unit prefixes and exponents. What you are learning builds upon them. Knowledge is cumulative. If you have a gap, it will come up again and again until it's filled.
Yes it s true
 

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