- #1

bingoboy

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## Homework Statement

I'm plotting a man jumping over a car for maths and I'm trying to find the critical velocity at which the car has to travel for the jumper to make it safeley over the car the man's jump is approximated by the parabola y= -0.0176x^2 + 0.3595x - 0.2794 and restricted by the height of the car y=1.225

So basically I have units of metres on the y-axis and seconds on the x-axis and i want to find the area under the curve of y= -0.0176x^2 + 0.3595x - 0.2794 and restricted by the line y=1.225. However i know how to do all the Integral stuff the only trouble I'm having is with what the units will be for my answer

## Homework Equations

units of y-axis = metres

Units of x-axis = seconds

## The Attempt at a Solution

My best guess is the units will be m/s which is what will be of most use to me, however if it's not is there a way i can manipulate the graph to give me an answer in metre's per second i.e instead of t make it t^2 or somthing like that