University thermodynamics fundamental equation/identity derivation.

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SUMMARY

The fundamental thermodynamic identity, expressed as \(\left(\frac {\partial U}{\partial V}\right)_T = T\left(\frac {\partial P}{\partial T}\right)_V - P\), cannot be derived without incorporating the concept of entropy, as indicated by the relationship \(\left(\frac {\partial P}{\partial T}\right)_V = \left(\frac {\partial S}{\partial V}\right)_T\). The discussion emphasizes that entropy is a crucial component of thermodynamics, and attempts to derive the identity without it are fundamentally flawed. Additionally, the sign convention in the equations must be consistent for accurate derivation.

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  • Understanding of thermodynamic identities and equations
  • Familiarity with the concepts of pressure (P), temperature (T), and volume (V)
  • Knowledge of the first and second laws of thermodynamics
  • Basic grasp of state functions in thermodynamics
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  • Study the derivation of the fundamental thermodynamic identity using entropy
  • Explore the implications of the second law of thermodynamics on state functions
  • Investigate the relationships between pressure, temperature, and entropy in thermodynamic systems
  • Learn about the significance of sign conventions in thermodynamic equations
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Students and professionals in thermodynamics, physicists, and engineers seeking to deepen their understanding of thermodynamic identities and the role of entropy in thermodynamic equations.

kntsy
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Hi, how can i derive this fundamental identity "without using entropy"?
\left(\frac {\partial U}{\partial V}\right)_T = T\left(\frac {\partial P}{\partial T}\right)_V - P

I believe the above equation is purely thermal and has nothing to do with entropy and statistical mechanics but unfortunately the below identity is the key to this derivation:

\left(\frac {\partial P}{\partial T}\right)_V = \left(\frac {\partial S}{\partial V}\right)_T

of course:

dU=TdS-PdV
 
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What do you mean "without using entropy"? what do you mean by "purely thermal"?
Entropy is a fundamental quantity of thermodynamics. I don't see why you should want to leave it out of the game.

Btw. your last equation is wrong. (At least compared to the sign convention you use in the first two formulas, then the last one should be different.)
 
Thaakisfox said:
What do you mean "without using entropy"? what do you mean by "purely thermal"?
Entropy is a fundamental quantity of thermodynamics. I don't see why you should want to leave it out of the game.

Btw. your last equation is wrong. (At least compared to the sign convention you use in the first two formulas, then the last one should be different.)

sorry for the mistakes. In other words, can we derive the first equation just using P,T,V; without using 2nd law(which defines entropy and shows that it is a "state" function)?
 

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