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## Homework Statement

The 100 kg block shown in the diagram takes 6.0s to reach the floor 1.0m below after being released from rest. What is the mass of the block on the left?

## Homework Equations

Newton's Third Law

F=ma

F (a on b) = -F (b on a)

## The Attempt at a Solution

I don't even know where to start, I was sick last class and can't figure out how to do this from the textbook. I've tried so far:

T1 = tension rope 1

T2 = tension rope 2

t0= 0s

t1= 6s

d=1.0m

g=9.8m/s^2

m1=unknown, find

m2=100kg

mass M: Fy = 0

T1-mg=0

T1=mg

T2= mg = (100kg)(9.8m/s^2)

= 980N

And now I'm lost.