Unraveling the Mystery: Comparing Neutralisation of HCl and CH3COOH

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SUMMARY

The discussion clarifies that both 25 cm3 of 1 mol/dm3 ethanoic acid (CH3COOH) and 25 cm3 of 1 mol/dm3 hydrochloric acid (HCl) require the same amount of sodium hydroxide (NaOH) for complete neutralization, despite the differing strengths of the acids. Ethanoic acid is a weak acid that partially dissociates, while HCl is a strong acid that fully dissociates. The misconception that more NaOH is needed for strong acids is addressed, emphasizing that neutralization depends on the number of moles of acid present, not their dissociation characteristics.

PREREQUISITES
  • Understanding of acid-base neutralization reactions
  • Knowledge of strong vs. weak acids
  • Familiarity with chemical equations for neutralization
  • Basic principles of molarity and volume in solutions
NEXT STEPS
  • Study the dissociation of weak acids, specifically acetic acid (CH3COOH).
  • Learn about the properties and reactions of strong acids, focusing on hydrochloric acid (HCl).
  • Explore the concept of molarity and how it applies to neutralization reactions.
  • Investigate the principles of mass conservation in chemical reactions.
USEFUL FOR

Chemistry students, educators, and anyone interested in understanding acid-base reactions and their applications in laboratory settings.

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Homework Statement


25 cm3 of 1 mol/dm3 ethanoic acid requires a smaller amount of sodium hydroxide for complete neutralisation than 25 cm3 of 1 mol/dm3 hydrochloric acid.
True or False?

2. The attempt at a solution

I selected true, but I was wrong. Both of them require the same amount of sodium hydroxide. How can this be?

Question 2:

In a dilute sugar solution, sugar molecules are widely separated, moving at random while water molecules are close together, moving at random.
True or False?

Attempt

I selected False. But I was wrong AGAIN! What's the reason?

Could you all help me with my questions. Thanks!
 
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Kyoma said:
I selected true, but I was wrong. Both of them require the same amount of sodium hydroxide. How can this be?

Why do you think they need different amount of base?

Similarly, try to explain your reasoning behind the answer to the second question.

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I think they need different bases cause ethanoic acid is a weak acid while HCL is a strong acid, thus you need more NaOH to neutralise a strong acid than a weak acid.

I figured out the second qns though, but I remember a qns vaguely about alcohol being dissolved into water and the mixture seems to have mass that didn't add up to the mass of water and alcohol or something like that. I didn't know whether it is the mass, density or volume that didn't add up.
 
Kyoma said:
I think they need different bases cause ethanoic acid is a weak acid while HCL is a strong acid, thus you need more NaOH to neutralise a strong acid than a weak acid.

Write reaction equations both for HCl and acetic acid neutralization with NaOH.

How much base needed to neutralize 1 mole of each acid?

I figured out the second qns though, but I remember a qns vaguely about alcohol being dissolved into water and the mixture seems to have mass that didn't add up to the mass of water and alcohol or something like that. I didn't know whether it is the mass, density or volume that didn't add up.

Volume is not additive. Mass is additive, that's mass conservation in action. But I fail to see how volume being not additive is relevant to the question.
 
Both require 1 mole... But even if both acids have 1 mole of particles, HCL would have more hydrogen ions since ethanoic acid dissociates partially and there would be CH3COOH molecules left intact in the water.

I figured out qns 2. Thanks.
 
Kyoma said:
Both require 1 mole... But even if both acids have 1 mole of particles, HCL would have more hydrogen ions since ethanoic acid dissociates partially and there would be CH3COOH molecules left intact in the water.

You are mistaking dissociation with neutralization. Yes, pH of HCl solution is lower than pH of acetic acid solution, no, it doesn't mean it requires more base for neutralization.

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