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Unusual question regarding torque

  1. Sep 27, 2009 #1
    two equivalent mases, m, are placed on two corners of a triangle with 3 sides each of length a (i.e an equilateral traingle). The third corner is fixed (not free to move).
    The triangle orginally starts with one side perfectly vertical. Gravity acts downward intially, calculate the accelerations of the masses right after the system is let go .
  2. jcsd
  3. Sep 27, 2009 #2
    Find torque and moment of inertia around the fixed point

    Use torque = moment of inertioa X rotational acceleration
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