Uranium isotopes with m in superscript

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Discussion Overview

The discussion centers on the notation used for uranium isotopes, specifically the meaning of the superscript "m" and the significance of the "+" sign in the context of nuclear spin and parity. It involves conceptual clarification regarding isotopes and their properties.

Discussion Character

  • Conceptual clarification

Main Points Raised

  • One participant inquires about the meaning of the "m" in the notation of uranium isotopes, specifically in 234mU, suggesting a lack of understanding of its significance.
  • Another participant explains that "m" stands for "metastable," referring to nuclear isomers with higher energy and relatively long half-lives.
  • A separate inquiry is made regarding the "+" next to the spin value of 0, questioning its meaning and suggesting confusion over its interpretation.
  • Another participant clarifies that the "+" indicates parity rather than a sign for spin.

Areas of Agreement / Disagreement

Participants appear to agree on the meanings of both the "m" and the "+" sign, with responses indicating that the questions raised have been satisfactorily answered.

Contextual Notes

The discussion does not delve into the implications of metastable states or parity in detail, leaving potential nuances unexplored.

nomadreid
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On the page https://en.wikipedia.org/wiki/Isotopes_of_uranium, some of the superscripts have, besides the atomic number, also an "m". For example, besides the usual isotope 234U with spin 0+, there is also the isotope 234mU (with nuclear spin 6-). What is this "m"?

While I am at it, what is the "+" next to the 0? +0 = -0, no? (It can't be the charge, given the "6-" for the other one.)
 
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m is abbreviation for "metastable". This signifies "nuclear isomers" - nuclear states which have higher energy than some other state of same neutron and proton number and relatively long half-life.
 
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thank you very much, snorkack. That completely answers the first question.
 
nomadreid said:
While I am at it, what is the "+" next to the 0? +0 = -0, no? (It can't be the charge, given the "6-" for the other one.)
It is the parity. It is not a sign for the spin.
 
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Thanks very much, mfb. That completely answers the second question.
Super! both questions wonderfully answered.
 

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