Use Graph to Determine Limit: Calculating Limits with Piecewise Functions

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Summary:: Graphs and Limits

Use the graph to determine the limit of the piecewise function as x tends to 1.

Let me see.

lim of (-x + 3) as x-->1 from the left is 2.

lim of (2x) as x-->1 from the right is 2.

I can safely say that the limit of f(x) as x tends to 1 from the left and right simultaneously is 1.

The limit of f(x) is 1.

Correct?
 

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nycmathguy said:
Summary:: Graphs and Limits

lim of (-x + 3) as x-->1 from the left is 2.

lim of (2x) as x-->1 from the right is 2.

I can safely say that the limit of f(x) as x tends to 1 from the left and right simultaneously is 1.

The limit of f(x) is 1.

Correct?

Typo ?

##\ ##
 
BvU said:
Typo ?

##\ ##

Yes, big time typo. The limit is clearly 2 not 1. I was rushing through my first reply. Thank you for pointing out my typo. I will repost.
 
I MADE A TYPO AND THUS, DECIDED TO REPOST ORIGINAL THREAD.

Use the graph to determine the limit of the piecewise function as x tends to 1.

Let me see.

lim of (-x + 3) as x-->1 from the left is 2.

lim of (2x) as x-->1 from the right is 2.

I can safely say that the limit of f(x) as x tends to 1 from the left and right simultaneously is 2.

The limit of f(x) is 2.

P. S. Having fun with calculus so far. Hoping the excitement does not run out.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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