Use integration to find the sum of a series

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Homework Help Overview

The problem involves finding the sum of a series using integration, specifically the limit as n approaches infinity of a series involving fractions with n in the numerator and squared terms in the denominator.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss constructing a function that relates to the series for integration, with one suggesting bounding the sum by integrals and another proposing the equivalence of the sum to a Riemann sum.

Discussion Status

The discussion includes various approaches to relate the series to integrals, with some participants expressing uncertainty about the construction of the function needed for integration. There is acknowledgment of different interpretations and methods being explored without reaching a consensus.

Contextual Notes

Participants are considering the implications of transforming the series and the limits involved in the integration process, with some noting the challenge of finding an appropriate function for integration.

raopeng
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Homework Statement


Find the sum using integration: [itex]lim_{n→∞} \frac{n}{(n+1)^2} + ... + \frac{n}{(2n)^2}[/itex]


Homework Equations





The Attempt at a Solution


I think this requires a clever construction of a series of an finite integral which after integration gives the series. Then it can be solved by summing up the series inside the integral then integrate the whole thing. But now what is bothering me is how to construct such a function, every function I have tried seems remotely far from the series in the question. Thanks for your time.
 
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How about bounding the sum by a pair of integrals over (n, 2n)?
 
Or show that the given sum is equivalent to a Riemann sum for some function. So taking the limit is equivalent to finding the integral.
 
Oh thanks so much!
 
I transform the series in this way: [itex]Ʃ_{k=1} ^{n} \frac{1}{(1+k/n)^2 n}[/itex] which turns into an integral [itex]\int^1 _0 \frac{dx}{(1+x)^2}[/itex]. An integration gives 1/2.
 

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