Use trig identities to show that

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SUMMARY

The discussion focuses on proving the trigonometric identity cos(tan^(-1)(x)) = 1/√(1+x^2) for the interval −π/2 < x < π/2. Participants emphasize the application of Pythagorean identities and geometric reasoning, specifically using the right triangle definition of the tangent function. By considering tan^(-1)(x) as an angle with an opposite side of x and an adjacent side of 1, the cosine can be derived using the relationship between the sides of the triangle.

PREREQUISITES
  • Understanding of trigonometric identities
  • Knowledge of inverse trigonometric functions
  • Familiarity with Pythagorean theorem
  • Basic geometry involving right triangles
NEXT STEPS
  • Study the derivation of trigonometric identities using right triangles
  • Learn about the properties of inverse trigonometric functions
  • Explore the relationship between sine, cosine, and tangent
  • Practice solving problems involving Pythagorean identities
USEFUL FOR

Students studying trigonometry, mathematics educators, and anyone looking to deepen their understanding of trigonometric identities and their applications in geometry.

ivan_x3000
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Homework Statement


use trig identities to show that

(b) cos(tan^(−1)[x])=1/√(1+x^2) for −1/2π<x<1/2π.


Homework Equations


i think Pythagoras has to applied but that is geometric reasoning hmm


The Attempt at a Solution


 
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Maybe try bringing ##\sin(\tan^{-1}(x))## into the picture?
 
ivan_x3000 said:

Homework Statement


use trig identities to show that

(b) cos(tan^(−1)[x])=1/√(1+x^2) for −1/2π<x<1/2π.


Homework Equations


i think Pythagoras has to applied but that is geometric reasoning hmm


The Attempt at a Solution


tan^(-1)(x) represents an angle whose opposite side is x and whose adjacent side is 1. Use that geometry to figure out the cosine.
 
ivan_x3000 said:

Homework Statement


use trig identities to show that

(b) cos(tan^(−1)[x])=1/√(1+x^2) for −1/2π<x<1/2π.


Homework Equations


i think Pythagoras has to applied but that is geometric reasoning hmm


The Attempt at a Solution


cos → sec → tan
 

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