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## Homework Statement

A 2.0 kg block is acted on by the following force

Force=[(2N/m)x-(5N/m

^{2})x

^{2}]{ihat}+[(13N/(1/m

^{2})x

^{2}-(6/m)x+7)e

^{-x^2/(2m^2)}cos{(2∏)x/3m}]{jhat}

as the object moves horizontally along a surface. In the expression for the force, x indicates the position of the block along the horizontal axis. The coefficient of kinetic friction between the block and the horizontal surface is 0.05. How much work does the given force do on the block as the block moves horizontally along the surface from x=0m to x=2.0m?

N is Newtons

m is Meters

## Homework Equations

I am not sure...

## The Attempt at a Solution

I have not attempted it because I am not sure where to start at all!!!!