(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 2.0 kg block is acted on by the following force

Force=[(2N/m)x-(5N/m^{2})x^{2}]{ihat}+[(13N/(1/m^{2})x^{2}-(6/m)x+7)e^{-x^2/(2m^2)}cos{(2∏)x/3m}]{jhat}

as the object moves horizontally along a surface. In the expression for the force, x indicates the position of the block along the horizontal axis. The coefficient of kinetic friction between the block and the horizontal surface is 0.05. How much work does the given force do on the block as the block moves horizontally along the surface from x=0m to x=2.0m?

N is Newtons

m is Meters

2. Relevant equations

I am not sure...

3. The attempt at a solution

I have not attempted it because I am not sure where to start at all!!!!

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# Using a Force equation to find out how much WORK is done.

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