I can do the solution, I do not understand the theory!(adsbygoogle = window.adsbygoogle || []).push({});

Here it is:

Using a pendulum to determine g using T = 2π√(l/g)

(that little n looking thing is pi)

(given l and T)

So, then we get

T^2 = (4π^2/g) x l

This is where I get lost.

Supposedly, I am to make the equation T^2 = kl (where k is the group of constants)

Then, I am to compare this formula with the general equation for a straight line y=kx.

Thus, k = m (of a graph, where vertical T^2 and horizontal l is the axis)

Why/how does k = m ?

k being (4π^2/g)

and m being the gradient of my graph?

______________

Thank you!

**Physics Forums - The Fusion of Science and Community**

# Using a pendulum to determine g using T = 2π√(l/g)

Have something to add?

- Similar discussions for: Using a pendulum to determine g using T = 2π√(l/g)

Loading...

**Physics Forums - The Fusion of Science and Community**