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Using Ampere's law to find B just outside finite solenoid

  1. Nov 28, 2010 #1
    1. The problem statement, all variables and given/known data

    We have a solenoid of radius a, length L, with ends at z = +/- L/2. The problem is to use Ampere's law to show that the longitudinal magnetic induction just outside the coil is approximately

    [tex] B_z (\rho=a^+, z) \approx \left(\frac{2 \mu_0 N I a^2}{L^2} \right) \left(1+ \frac{12 z^2}{L^2}- \frac{9 a^2}{L^2} + \ldots \right) [/tex]

    (This is part b of problem 5.5 in Jackson 3rd edition).
    2. Relevant equations

    Ampere's law: [tex] \oint B \cdot dl = \mu_0 I [/tex]

    3. The attempt at a solution
    I'm pretty sure I'm thinking about this too simplistically, which is why I'm stuck. For an infinite solenoid, the magnetic induction outside is 0. Since we've got a finite solenoid, there are obviously fringing effects of some sort and I guess we can't expect the field to be 0 outside anymore (though it should be reasonably small compared to the field on axis in the center of the solenoid).

    I can't figure out what to do differently with Ampere's law though. Does my amperian loop enclose the coils over the full length L of the solenoid or just a short bit? What I was initially thinking was that if my amperian loop encloses all of them, then

    [tex] \oint B \cdot dl = BL = \mu_0 I N L \rightarrow B = \mu_0 N I \hat{z} [/tex]

    but this is the result you get with the infinite solenoid inside the solenoid, and is clearly not what I need to have since there's nothing to expand on... so I guess I'm not sure how to set this up. Can anyone help?
     
  2. jcsd
  3. Nov 29, 2010 #2

    kreil

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    Gold Member

  4. Mar 19, 2011 #3
    Hey guys, how do you know that for an infinite solenoid, the magnetic induction outside is 0?
     
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