Using Compressed Air Tools Outdoors: Can it be Done?

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SUMMARY

The discussion focuses on the feasibility of using compressed air tools outdoors, specifically a bolt wrench powered by a 50 L air tank at 50 bars. The calculations demonstrate that at -20 °C, the air tank can deliver approximately 23.76 moles of air, allowing the wrench to operate for about 2.5 minutes before pressure drops below the required 10 bar. The solution provided is confirmed to be correct, as it accurately calculates the usable air and the consumption rate of the wrench.

PREREQUISITES
  • Understanding of gas laws, specifically the Ideal Gas Law.
  • Familiarity with pressure and temperature conversions.
  • Basic knowledge of air consumption rates for pneumatic tools.
  • Experience with mole calculations in chemistry.
NEXT STEPS
  • Study the Ideal Gas Law and its applications in real-world scenarios.
  • Research the effects of temperature on gas pressure and volume.
  • Learn about the design and specifications of pneumatic tools.
  • Explore safety measures for using compressed air tools outdoors.
USEFUL FOR

This discussion is beneficial for mechanical engineers, automotive technicians, and anyone involved in the use of pneumatic tools in varying environmental conditions.

stephenranger
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Homework Statement


Car mechanics use compressed air tools to open bolts. Instead of using an air compressor one can also use a tank of pressurized air. There is an air tank with a volume of 50 L to work with. The pressure of the tank is 50 bars when it is stored indoors at 20 °C. The bolt wrench needs at least 10 bar pressure to operate.

Homework Equations


How long can the mechanics use the bolt wrench outdoors at -20 °C if it consumes 200 L/min of air at normal pressure ? the normal pressure is 1.0 bar.

The Attempt at a Solution


R = 8.314E-2 L bar/(mol K)
the tank holds this many moles
n = PV/RT = 50(50) / (8.314E-2 * 293) = 102.6 mol of air
at -20° the pressure will be
P = nRT/V = 102.6(8.31E-2)(253)/50 = 43.174 bar
How many moles can be delivered from 43.174 bar down to 10 bar, the lower limit?
all else being equal, moles are proportional to pressure
X mol / 102.6 mol = 10 bar / 43.174 bar
X mol = 23.76 mol (useful amount of gas)
How much does the wrench use per minute?
n = PV/RT = 1.0 (200) / (8.314E-2 * 253) = 9.508 mol per minute
finally
23.76 mol / 9.508 mol/min = 2.499 or 2.5 min to 2 sig figs or 150 s

Is the solution correct ?
 
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Your X mol seems to be the amount of gas left in the tank when the wrench stops working, not the amount of gas used.
 

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