Using Current Density to find Total Current

Click For Summary
SUMMARY

The discussion focuses on calculating the total current flowing through a cylindrical wire with a given current density defined as J = I_0 (x^2 / R^4)−k. The integral for total current is expressed as I = ∫ J · dA, where dA is assumed to be R dR dx. The initial attempt at solving the integral led to I = I_o (x^3 / 3)(-R^{-2}/2)−k. Participants emphasize the importance of clearly defining variables, particularly the meaning of 'x' in the context of cylindrical coordinates.

PREREQUISITES
  • Understanding of cylindrical coordinates in physics
  • Familiarity with current density and its mathematical representation
  • Knowledge of integral calculus, specifically double integrals
  • Basic concepts of electromagnetism related to current flow
NEXT STEPS
  • Study the derivation of current density in cylindrical geometries
  • Learn about the application of double integrals in physics problems
  • Explore the relationship between current density and total current in different geometries
  • Review the principles of electromagnetism, focusing on current flow in conductors
USEFUL FOR

Students and educators in physics, electrical engineering, and anyone involved in solving problems related to current flow in cylindrical conductors.

slavito
Messages
3
Reaction score
0

Homework Statement



Suppose a wire has a radius R and a current density of J = I_0 \frac{x^2} {R^4}\hat{k}. Taking the wire to have cylindrical geometry, calculate the total current flowing down the wire, defined as I = \int J \cdot \vec{dA}.


Homework Equations


J = I_0 \frac{x^2} {R^4}\hat{k}
I = \int J \cdot \vec{dA}


The Attempt at a Solution



Here, I assumed that dA = R dR dx . I then attempted to do the Integral. I assumed Io was a constant, so I pulled that out of the Integral, giving me...

I = I_o\int x^2\cdot \vec{dx} \int R^{-3} \cdot \vec{dR}

Evaluating, I got...

I = I_o\frac{x^3}{3}\frac{R^{-2}}{-2}\hat{k}

I have no idea if this is right or wrong. I don't even know if I'm on the right track. Please, any sort of help you could give me would be greatly appreciated!
 
Physics news on Phys.org
welcome to pf!

hi slavito! welcome to pf! :smile:

i don't understand what x is :confused:

does x mean distance from the centre (which we would usually call "r")?

or is x one of the usual x,y,z coordinates (with the wire pointing along the z axis)?

(and R is a constant, so you can't have dR)
 
Assuming the wire axis and the current run along the z axis and the wire axis is centered at x=y=0:

what is a sliver of area of width dx and height = distance between 2 points on the circle at x? What is then the current within that area?

Tiny-tim is of course right about R and he's right about the need to define your problem fully. Most posters for some reason don't post the problem as handed to them.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K