Using differentials to estimate error

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SUMMARY

This discussion focuses on using differentials to estimate the error in calculating the hypotenuse of a right triangle with one side measuring 12 cm and an opposite angle of 30°, subject to a ±1° error. The formula derived is c = 12(sin(θ))⁻¹, where c represents the hypotenuse. The differential dc is calculated as dc = -12(sin(θ))⁻² cos(θ) dθ, with θ set to 30° and dθ expressed in radians as ±π/180. This approach allows for precise error estimation in trigonometric calculations.

PREREQUISITES
  • Understanding of trigonometric functions, specifically sine and cosine.
  • Familiarity with the concept of differentials in calculus.
  • Knowledge of how to convert degrees to radians.
  • Basic geometry of right triangles.
NEXT STEPS
  • Study the application of differentials in error estimation in calculus.
  • Learn about trigonometric identities and their derivatives.
  • Explore the conversion between degrees and radians in mathematical contexts.
  • Investigate real-world applications of differentials in engineering and physics.
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Students and professionals in mathematics, engineering, and physics who are interested in error analysis and the application of calculus to solve practical problems involving trigonometry.

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one side of a right triangle is known to be 12 cm long and the opposite angle is measured as 30°, with a possible error of ±1°.
(a) Use differentials to estimate the error in computing the length of the hypotenuse.
 
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I have retitled your thread so that the title now reflects the nature of the question being asked.

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Buka said:
one side of a right triangle is known to be 12 cm long and the opposite angle is measured as 30°, with a possible error of ±1°.
(a) Use differentials to estimate the error in computing the length of the hypotenuse.
[math]sin(\theta)= \frac{a}{c}[/math] so that [math]c= \frac{a}{sin(\theta)}= \frac{12}{sin(\theta)}= 12(sin(\theta))^{-1}[/math]. Differentiating, [math]dc= -12(sin(\theta))^{-2} cos(\theta) d\theta[/math].

Take [math]\theta= 30^o[/math] and [math]d\theta= \pm\frac{\pi}{180}(1)= \pm\frac{\pi}{180}[/math] (because the derivative of sine assumes the angle is in radians, not degrees).
 

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