Using Feynman rules to calculate amplitude

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
4 replies · 3K views
Higgsy
Messages
18
Reaction score
0
Given a diagram, how is one supposed to apply the feynman rules to calculate the feynman amplitude?
 

Attachments

  • Screen Shot 2015-11-24 at 4.33.10 AM.png
    Screen Shot 2015-11-24 at 4.33.10 AM.png
    2.2 KB · Views: 651
Physics news on Phys.org
Srednicki. But these are not calculated in srednicki. To clarify, they are the vacuum feynman diagrams for $$\phi ^{4}$$ scalar theory
 
These are vacuum "bubble" diagrams, i.e., they contribute to the vacuum->vacuum transition amplitude in perturbation theory. To evaluate S-matrix elements you don't need them, because they cancel in the LSZ reduction formula via the correct normalization of the scattering amplitude.

To formally evaluate them you just use the Feynman rules and use any regularization procedure you like. Dimensional regularization is pretty convenient also in ##\phi^4## theory. Take the "8 diagram". The vertex stands for ##-\mathrm{i} \lambda/4!##. Then you have 3 ways to connect the first leg at the vertex with another line and then only 1 to connect the remaining legs. Thus you have a symmetry factor ##3##. The final dim-reg expression is.
$$\mathrm{i} V=\frac{\mathrm{i} \lambda \mu^{2 \epsilon}}{8} \int_{\mathbb{R}^d} \frac{\mathrm{d}^d l_1}{(2 \pi)^d} \int_{\mathbb{R}^d} \frac{\mathrm{d}^d l_2}{(2 \pi)^d} \frac{1}{(m^2-l_1^2)(m^2-l_2^2)},$$
where ##d=4-2 \epsilon## is the dimension of space-time.