- #1

- 22

- 0

## Homework Statement

At any time t seconds the distance x metres of a particle moving in a straight line from a fixed point is given by x = 4t + ln(1-t). Using the function of a function rule, determine

A.) the initial velocity and acceleration

## The Attempt at a Solution

I had a go at the velocity section and got the following.

x = 4t + ln(u)

x = 12 - 4u + ln(u)

du/dt = 0 - 1 = -1 (dx/dt = dx/du x du/ds)

v = dx/dt = (-4 + 1/u) x (-1) - (4 - 1/u)

= 4 - 1/u = 4 - 1/3-t

t=0

dx/dt = 4 - 1/3-0

= 4 - 1/3

3 1/3 (initial velocity)

I think this is right, I know it looks complex but my question is how do I go about finding out the acceleration from this. Any help much appreciated