Alright I have the question: Find dy/dx by implicit differentiatin ysin(x^2) = xsin(y^2) Basically you jus take the derivative of both sides and solve for dy/dx, but I was unsure whether or not my differentation was right. If someone could just get me started in the right direction for this equation I'd be thankful because I'm sure I can finish the rest. [ysin(x^2)]' = [xsin(y^2)]' ycos(x^2)*2 = xcos(y^2)*2 Is what I tried but I know that is completely wrong because you have to use the chain rule for both sides. I feel so silly right now because the other examples make more sense, yet this one doesn't haha. Thanks a lot guys.