Using molarity in stoichiometry problems

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Discussion Overview

The discussion revolves around a stoichiometry problem involving the calculation of molarity for aluminum sulfite in a reaction with barium chloride. The context includes balancing chemical equations and determining molarity based on given concentrations and volumes.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents a stoichiometry problem and outlines the balanced chemical equation for the reaction between aluminum sulfite and barium chloride.
  • The participant notes the need to find the molarity of aluminum sulfite but only has the molarity of barium chloride.
  • Another participant questions the completeness of the information provided, pointing out the absence of the volume of barium chloride or any product information.
  • A different participant suggests assuming a certain amount of barium chloride to proceed with the calculations.
  • One participant humorously notes that the teacher may have written the problem incorrectly, implying that there may be missing information.

Areas of Agreement / Disagreement

Participants generally agree that the problem lacks sufficient information to proceed with the calculations, and there is no consensus on how to resolve the issue due to the missing variables.

Contextual Notes

The discussion highlights limitations in the problem statement, specifically the absence of the volume of barium chloride and the products involved, which are necessary for completing the stoichiometric calculations.

lzh
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Homework Statement



What is the molarity of 50.0mL sample of aluminum sulfite when it is reacted with 3.00M solution of barium chloride? The product of this double replacement is aluminum chloride and barium chloride.

Homework Equations


The first thing i did was balance(all number after forumula is subscript):
Al2(SO3)3 + 3BaCl2 -> 2AlCl3 + 3BaSO3

molarity is :
Mol of solute/ L of solution
It gives me the volume so i need to find the mol

The Attempt at a Solution



as my teacher said, its best to always start with the value other than M. So:
.050L Al2(SO3)3 * something to take it out of liter and into mols. But in order to do that i need to know Al2(SO3)3's molarity, and i only know barium chlorides's.

I must be not considering something pertaining to barium chloride, but I'm not sure, can someone lend me a hand?
 
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That's all the variables you have? It doesn't say anything about the volume of Barium Chloride or any of the products? I may be missing something as I just woke up, but I can't see what to do without something else.
 
yeah that's all it gave me...
 
I would just assume that I had 3.00 mol Barium Chloride then. There has to be another variable...
 
lol, the teacher had the problem wrote wrong
 

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