Using Right Hand Thumb Rule to Determine Resultant Force

Click For Summary
SUMMARY

The discussion centers on the application of the right-hand thumb rule in determining the direction of torque resulting from a cross product of two vectors, specifically the moment defined as M = r × F. Participants clarify that the cross product does not yield a resultant force but rather a torque, which is directionally dependent on the order of the vectors. The standard definition of torque is established as M = r × F, emphasizing that reversing the order (M = F × r) alters the sign of the torque. The right-hand rule is confirmed as the method for visualizing the direction of torque.

PREREQUISITES
  • Understanding of vector cross products
  • Familiarity with torque and its mathematical representation
  • Knowledge of the right-hand rule for vector direction
  • Basic principles of mechanics and force interactions
NEXT STEPS
  • Study the mathematical properties of vector cross products
  • Learn about torque applications in rotational dynamics
  • Explore the right-hand grip rule for visualizing torque direction
  • Review standard definitions and conventions in mechanics textbooks
USEFUL FOR

Students of physics, mechanical engineers, and anyone interested in understanding the principles of torque and vector mathematics.

goldfish9776
Messages
310
Reaction score
1
the moment is r X F = rFsin tetha
which means r is projected to F , am i right . If so , then the resultant force should point downwards( by using right hand thumb rule) , am i right?
 

Attachments

  • DSC_0068.JPG
    DSC_0068.JPG
    48.5 KB · Views: 563
Last edited by a moderator:
Physics news on Phys.org
I think you are thinking right, but it is difficult to tell because you use the wrong nomenclature. First of all, a cross product is not a projection. Second, the result of that cross product is not a force, it is a torque (which is the common name for a force moment of this form). "Resultant" is normally used for the result of a vector sum, not for a cross product.
 
Orodruin said:
I think you are thinking right, but it is difficult to tell because you use the wrong nomenclature. First of all, a cross product is not a projection. Second, the result of that cross product is not a force, it is a torque (which is the common name for a force moment of this form). "Resultant" is normally used for the result of a vector sum, not for a cross product.
so , do you mean the book is wrong? the moment ( so-called resultant force ) should be pointing downward if I use M=r x F
If i use M= F X r , then the torque should be acting upwards?
 
Last edited:
goldfish9776 said:
so , do you mean the book is wrong? the moment ( so-called resultant force ) should be pointing downward if I use M=r x F
If i use M= F X r , then the torque should be acting upwards?
No, the book is correct. Again, it is not a projection. And for the second time: a moment is not a resultant force.
 
Orodruin said:
No, the book is correct. Again, it is not a projection. And for the second time: a moment is not a resultant force.
so , no matter M= r x F or M= F x r , the torque is in downward direction ?
 
goldfish9776 said:
so , no matter M= r x F or M= F x r , the torque is in downward direction ?
No, you cannot go around changing the definitions arbitrarily. The cross product changes sign if you change the order and only one of the definitions is standard. In the example in the book, the torque should point up.
 
Orodruin said:
No, you cannot go around changing the definitions arbitrarily. The cross product changes sign if you change the order and only one of the definitions is standard. In the example in the book, the torque should point up.

the book changes the order from the top to the bottom . the book give M= r x F at the upper part , then it changes to M= F ( r sin tetha ) at the bottom. Which is the standrad definition ?
 
It does not change order, the second equation is just the magnitude and all quantities in it are scalars. The order in a product of scalars is irrelevant.
 
Orodruin said:
It does not change order, the second equation is just the magnitude and all quantities in it are scalars. The order in a product of scalars is irrelevant.
thanks , Orodruin . Everything is clear now
 
  • #10
Orodruin said:
No, you cannot go around changing the definitions arbitrarily. The cross product changes sign if you change the order and only one of the definitions is standard. In the example in the book, the torque should point up.
so the standard definition of moment is M= r x F , not M= F x r ?
 
  • #11
goldfish9776 said:
so the standard definition of moment is M= r x F , not M= F x r ?
Yes, because in general, r × F ≠ F × r, because the vector cross product does not commute.
 
  • #12
SteamKing said:
vector cross pr
SteamKing said:
Yes, because in general, r × F ≠ F × r, because the vector cross product does not commute.
Can you explain why is it r × F ? but not F × r
 
  • #13
goldfish9776 said:
Can you explain why is it r × F ? but not F × r
This is a definition, it is how torque is defined. You could have defined it the other way around, but you would then have to go back and rewrite all textbooks using the standard definition.
 
  • #14
goldfish9776 said:
Can you explain why is it r × F ? but not F × r
In order to keep track of everything and keep signs straight, the "right had rule" is used. With the right hand, r x F makes r ~ the first finger, F ~ the second finger, and the torque is the thumb. If you mix up the sign convention, everything will get impossibly confusing.
 
  • #15
FactChecker said:
In order to keep track of everything and keep signs straight, the "right had rule" is used. With the right hand, r x F makes r ~ the first finger, F ~ the second finger, and the torque is the thumb. If you mix up the sign convention, everything will get impossibly confusing.
what do u mean by r ~ the first finger, F ~ the second finger ? we have only finger point from r to the F , right ?
 
  • #16
To use the right-hand-rule on r x F, take your right hand and:
Hold your index finger, your middle finger, and your thumb all perpendicular to each other to form a coordinate system (index finger straight ahead, middle finger in at a right angle, thumb straight up)

With your fingers held that way, twist your hand so that:
Point the index finger in the direction of r.
Point the middle finger in the direction of the rejection of F on r. (The rejection of F on r is the component of F that is perpendicular to r.)

Your thumb will then point in the direction of the torque vector.
 
Last edited:
  • #17
FactChecker said:
To use the right-hand-rule on r x F, take your right hand and:
Hold your index finger, your middle finger, and your thumb all perpendicular to each other to form a coordinate system (index finger straight ahead, middle finger in at a right angle, thumb straight up)

With your fingers held that way, twist your hand so that:
Point the index finger in the direction of r.
Point the middle finger in the direction of the rejection of F on r. (The rejection of F on r is the component of F that is perpendicular to r.)

Your thumb will then point in the direction of the torque vector.
then how about the right hand grip rule ? how to use it ?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
1K
  • · Replies 27 ·
Replies
27
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K