1. The problem statement, all variables and given/known data . In the diagram below, the line AB is at x = 1 and the line BD is at y = 1. Use Stokes’ theorem to find the value of the integral ∫s2(∇xV)⋅dS where S2 where S2 is the curved surface ABEF, given that AF and BE are straight lines, and the curve EF is in the y-z plane (i.e. the plane x = 0), explaining how you are able to do this. [Hint: Consider the value of ∇×V on the vertical surfaces OAF, BED and ODEF. You should not need to actually calculate any integrals.] 2. Relevant equations Stokes' theorem - ∫s2(∇xV)⋅dS = ∫CV⋅dr Earlier on in the question I used Stoke's theorem to calculate the area and line integral for the path C and the area enclosed by C. The answer was 2. I also calculated that (∇xV)=(3x2+3y2)k 3. The attempt at a solution I really have no idea for this part of the question. These are the types of questions I struggle at with vector calculus. I have a feeling it have something to do with the fact that at x=1 the line is straight. Also he has suggested we consider the value for (∇xV) when x and y are unchanged and we have already looked at when z is unchanged. Other than that I'm really not sure. A point in the right direction would be of great help.