Using the binomial theorem as an approximation

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SUMMARY

The discussion focuses on using the binomial theorem to approximate the value of 1/(√4.2) by expanding (1+x)^(-1/2). The initial attempt to substitute x=3.2 into the expansion resulted in inaccuracies due to the condition that x must be much less than 1 for the approximation to be valid. The correct approach involves rewriting (4.2)^(-1/2) as (4)^(-1/2)(1.05)^(-1/2), allowing for a more suitable expansion around a smaller x value. This method ensures that higher-order terms can be neglected, leading to a more accurate approximation.

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  • Understanding of the binomial theorem and its applications
  • Familiarity with Taylor series and approximations
  • Basic knowledge of calculus, specifically derivatives
  • Ability to manipulate algebraic expressions and functions
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  • Learn about Taylor series and their convergence criteria
  • Explore the implications of approximating functions near points of interest
  • Investigate other mathematical tools for approximations, such as Newton's method
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Mathematicians, physics students, and anyone interested in numerical methods and approximations using the binomial theorem.

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Use the binomial expansion of (1+x)^(-1/2) to find an approximation for 1/(rt4.2).

I've got the expansion of (1+x)^(-1/2) as 1-(1/2)x+(3/8)x^2...
but the obvious idea of substituting x=3.2 gives me the wrong answer. I think it's something to do with the expansion being valid but can't remember. Any help would be much appreciated.
 
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The expansion is valid for all values of [itex]x[/itex], but only useful when [itex]x \ll 1[/itex]. If you let x=3.2, then successive terms in the expansion become larger and larger ([itex]3.2^3 >3.2^2[/itex]). But if [itex]x \ll 1[/itex], then successive terms become smaller and smaller and so only the first few terms are large enough to make a significant contribution to the total value, and you can neglect higher order terms.

Try rewriting [itex](4.2)^{-1/2}[/itex] as [itex]4^{-1/2}(1.05)^{-1/2}=(1/2)(1.05)^{-1/2}[/itex]; this way you can expand the square root about a much smaller x.
 
You would be better off expanding (4+x)1/2. Can you get the Binomial theorem expansion for that?
 

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