1. PF Contest - Win "Conquering the Physics GRE" book! Click Here to Enter
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Using TI 89 to apply central limit theorem

  1. Feb 10, 2010 #1
    (to find distribution of sample mean)


    P((X1 - μ) / σ/√n) < Z < (X2 - μ) / σ/√n)) = P(a < Z < b) = phi(b) - phi(a)

    where phi(z) = 1/sqrt(2*pi) * integral of exp(-z^2 / 2) dz from negative infinity to z


    I'm sure there's some statistical way of doing this with a TI 89, but how? The Normal cdf asks me for bounds, which I don't see what they would be here. so I figure that is not the correct function on the calculator. Using the calculator would be helpful since it's obviously not easy to solve this integral analytically.
  2. jcsd
  3. Feb 10, 2010 #2


    User Avatar
    Gold Member

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook