Valence Electron of CN: Discover the Atomic Structure of Cyanide

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SUMMARY

The valence electron count for the cyanide ion (CN-) is 10, not 9. This is determined by adding the valence electrons of carbon (4) and nitrogen (5), and accounting for the additional electron due to the negative charge of the ion. Therefore, the total for CN- is 4 + 5 + 1 = 10. Understanding group numbers of the constituent atoms is essential for calculating valence electrons accurately.

PREREQUISITES
  • Basic knowledge of atomic structure and electron configuration
  • Understanding of group numbers in the periodic table
  • Familiarity with ionic compounds and their charge implications
  • Concept of valence electrons in chemical bonding
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  • Research the periodic table and group numbers for elements
  • Learn about the concept of ionic charges and their effects on electron counts
  • Study molecular geometry and how it relates to valence electrons
  • Explore the properties of cyanide and its applications in chemistry
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Chemistry students, educators, and anyone interested in molecular structure and electron configuration in chemical compounds.

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Sry...but for some reason I can't start a new thread and i need a little help.

Is the valence electron of CN 9?
 
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Are you referring to the total number of valence electrons? And is it CN or CN- that you want this for?

Show us what you tried. How did you get the number 9?
 
unhip_crayon said:
Sry...but for some reason I can't start a new thread and i need a little help.

Is the valence electron of CN 9?

Perhaps the easiest way to figure this out, is to look at both of that atom's group numbers. This will tell you the number for valence electrons. For a molecule, just add those numbers.
 

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